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Olin [163]
2 years ago
13

What equation is graphed in this figure

Mathematics
1 answer:
Keith_Richards [23]2 years ago
3 0

Answer:

tatho you get the aswer

Step-by-step explanation:

all you have to do is add

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Megan creates a scale drawing of a car. The ratio of her scale drawing length to actual car
Alika [10]

Answer:

Givens

  • The length of the car in her drawing is 6 cm.
  • The scale is 3 cm : 2 m.
  • Ivan draws with a relation 2 cm : 1 m.

First, we need to find the actual length of the car using Megan's ratio.

If 2 centimeters is equivalent to 1 actual meter of the car, 6 centimeters of drawing would be equal to

M=6cm \times \frac{2m}{3cm} =4m

Therefore, the car is 4 meters long.

Now, using this information, we can find the length of the scale drawing of Ivan.

I=4m \times \frac{2cm}{1m}=8cm

Therefore, Ivan's drawing is 8 centimeters long.

6 0
3 years ago
Read 2 more answers
Fill in the gaps in the arithmetic sequence -3, _ ,_ , _, _, _ 12
lord [1]

Answer:

  -0.5, 2, 4.5, 7, 9.5

Step-by-step explanation:

The given terms are 6 apart, so the common difference is 1/6 of their difference:

  d = (12 -(-3))/6 = 15/6 = 5/2 = 2.5

Add 2.5 to each term to get the next one. Then the sequence is ...

  -3, <u>-0.5</u>, <u>2.0</u>, <u>4.5</u>, <u>7.0</u>, <u>9.5</u>, 12

8 0
3 years ago
Please help me i need it :)
Musya8 [376]

Answer:

I think the incenter of LO is 27 like ML

Step-by-step explanation:

because LO is almost the same of ML

5 0
2 years ago
What is 0.316 in expanded form.
RUDIKE [14]
Uhm, I'm pretty new to expanded form but I think it's something like:
(3 × 1/10) + (1 × 1/100) + (6 × 1/1000)
You can also write it as:
0.3 + 0.01 + 0.006
Let me know if you need working or anything!
7 0
3 years ago
Read 2 more answers
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
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