What is the equation of a line passing through the points 6,3 and -4,3 so y=?
1 answer:
Equation of a line using 2 points. first find the slope
m= (y2-y1)/(x2-x1)= (3-3)/(-4-6)= 0/-10 = 0
m=0
using y-y1=m(x-x1)
we get
y-3=0(x-6)
y-3=0
y=3 is the equation of the line
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Answer:
two angles- angle 6 and 7
It’s 3 points or more which lie in the same plane
Sq. rt 49t^4 * Sq. rt 2t= 7t^2sq.root 2t
it is c or b but i think c it is not b
A= a x b x sin of the angle
A= 13 x 21 x 0.98
A= 267.54
hope i helped :))
