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3 years ago

Ed & Heath won the grand

Mathematics

1 answer:

mestny [16]3 years ago

6 0

Answer:

224

Step-by-step explanation:

(100+12)*2

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Which of these choices represent a exponential pattern select all that apply.

Agata [3.3K]

The correct answer for the question that is being presented above is this one: "A. Division of skin cells every half hour; B. Small graph of y=x squared; C. y= 4 times 3 raised to x; D. y=2x raised to the 3." These choices represent an exponential pattern.

7 0

3 years ago

Ron needed to buy a new jacket for his upcoming ski trip. The ticket price of the jacket was $199.00. After the sales tax was ad

Levart [38]

Answer: 5%

Step-by-step explanation:

Given that:

Ticket price of jacket = $199

Final price after addition of sales tax = $208.95

Percentage sales tax on the jacket =?

Final price after addition of sales tax = price of jacket + amount of sales tax paid

208.95 = 199 + amount of sales tax paid

amount of sales tax paid = 208.95 - 199

amount of sales tax paid = $9.95

Let Percentage of sales tax = x

(x / 100) * 199 = 9.95

199x / 100 = 9.95

199x = 995

x = 5

Hence percent sales tax paid = 5%

8 0

3 years ago

Help & explain answer pls

AlekseyPX

The solution is (-2,4) she right both have the same solution because if you solve both of them you will get (-2,4)

5 0

3 years ago

What is the correct answer?

Tasya [4]

Given:

The function is

$f(x)=(x+3)^2(x-5)^6$

To find:

The zeros of the given function.

Solution:

The general form of polynomial is

$P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}$ ...(i)

where, a is a constant, $c_1,c_2,...,c_n$ are zeros of respective multiplicities $m_1,m_2,...,m_n$ .

We have,

$f(x)=(x+3)^2(x-5)^6$

On comparing this with (i), we get

$c_1=-3,m_1=2$

$c_2=5,m_2=6$

It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.

Therefore, the correct option is B.

5 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago