Answer:
The image of the point p is p'(\frac{1}{4},\frac{-5}{14}).
Step-by-step explanation:
The center of dilation is origin and the scale factor is \frac{1}{7}.
The coordinates of point p are
(\frac{7}{4},\frac{-5}{2})
If k is the scale factor and origin is the center of dilation, then
(x,y)\rightarrow (kx,ky)
Since the scale factor is \frac{1}{7} and the origin is the center of dilation, therefore
(x,y)\rightarrow (\frac{1}{7}x,\frac{1}{7}y)
The coordinates of image of p are
p(\frac{7}{4},\frac{-5}{2})\rightarrow p'(\frac{1}{7}\times \frac{7}{4},\frac{1}{7}\times \frac{-5}{2})
p(\frac{7}{4},\frac{-5}{2})\rightarrow p'(\frac{1}{4},\frac{-5}{14})
Therefore the image of the point p is p'(\frac{1}{4},\frac{-5}{14}).
Step-by-step explanation: hope this helps mark me as brainiest
