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zloy xaker [14]

3 years ago

13

A bag contains purple and orange marbles.Sam randomly takes out one marble and then returns it to the bag.He does this 18 times,

and 12 of those times an orange marble is pulled out.What is P(green)?

1 answer:

Rudik [331]3 years ago

7 0

I think 6 but how r u supposed to know how many marbles you started with

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Dmitry_Shevchenko [17]

Answer:

see below

Step-by-step explanation:

Popcorn is preferred by about 1/2 of the folks, so 3 of the 6 outcomes from a die roll will model this well. Only the 1st and 3rd choices show 3 outcomes representing Popcorn.

Hotdogs are preferred by about 1/6 of the folks, so 1 of the 6 outcomes from a die roll will model this well. Only the 1st and 2nd choices show 1 outcome representing Hotdogs.

Only the 1st choice models the preferences appropriately.

4 0

3 years ago

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Find all solutions of the equation in the interval [0,2π) sec(theta) +2=0

Komok [63]

I will first reveal the most obvious secret of trig: Most of the problems are 30/60/90 or 45/45/90 triangles of some sort.

$\sec \theta + 2 = 0$

$\dfrac{1 }{ \cos \theta} = -2$

$\cos \theta = - \frac 1 2$

The rule to remember is $\cos x = \cos a$ has solutions

$x = \pm a + 2 \pi k \quad$ integer $k$

Continuing where we left off, a cosine of -1/2 is a 30/60/90 triangle in the second or third quadrant; we pick second, and a little thought tells us the angle is $120^\circ$ .

$\cos \theta = - \frac 1 2$

$\cos \theta = \cos \frac {2\pi} 3$

$\theta = \pm \frac {2\pi} 3 + 2 \pi k \quad$ integer $k$

In the range we want, that's $k=0$ with the plus sign and $k=1$ with the minus, so

$\theta = \frac {2\pi} 3$ or $-\frac {2\pi} 3 + 2 \pi = \frac{4 \pi} 3$

$\theta = \frac {2\pi} 3$ or $\frac{4 \pi} 3$

6 0

3 years ago

there are 20 students in chess club. two students are to be selected for representing the club in a school meeting. in how many

Murljashka [212]

first way is play a match between all of them and select first Palace and second to be selected in the meeting

8 0

3 years ago

(sinA÷secA)÷(cosA÷sinA) =tan A

Sloan [31]

(Sin A/ secA) × ( sec A / cos A) = Sin A / cos A = tan A

Question should be cos A ÷ sec A

4 0

3 years ago

Determine if the two triangles are congruent. If they are, state<br> the condition.

RideAnS [48]

Answer:

HL

Step-by-step explanation:

Since we have two pairs of congruent sides with the included angle, one pair of which are the hypotenuses, then the triangles are congruent by HL.

5 0

3 years ago

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