SOLUTION
Given B is the midpoint of AC ABBC 1 and C is the midpoint of BD BCCD2 ie on adding 1 and 2 ART We get ABBCBCCD hence ABCD hence proved
Answer:
y>0
all positive real numbers
Step-by-step explanation:
the range is the output values
this will always be greater than 0
Range : y>0
Answer:
D, (6,1), (8,8), (12,22), (20,50)
Step-by-step explanation:
Hope this helps!! :D
Answer:
Easy, 4 units
Step-by-step explanation:
Answer:
<h3>B. -84</h3>
Step-by-step explanation:
Taking the determinant of the matrices we will have;
= 4x(5y) - 2x(3y)
= 20xy - 6xy
= 14xy
Given x = -2 and y = 3
Determinant = 14(-2)(3)
Determinant = -28*3
Determinant = -84
