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3 years ago

Am nevoie de 4 propoziții despre comportamentul vulpii,pls.Dau Coroana!

Biology

1 answer:

kkurt [141]3 years ago

8 0

Answer:

Vulpile sunt omnivore, ceea ce înseamnă că vor mânca în esență orice este o plantă sau un animal. Vulpile mănâncă animale mici, de la păsări la rozătoare, și mănâncă insecte mari, de la greieri până la gândaci. Vulpile mănâncă, de asemenea, fructe de pădure, nuci și fructe primăvara, vara și toamna. Una peste alta, vulpile sunt vânători experți care au o mare varietate în dieta lor.

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Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

$E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}} \Big )$

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

$E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}$

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

$100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\ 53.57 = \dfrac{4}{[K^+]_{in}}$

$[K^+]_{in} = \dfrac{4}{53.57}$

$[K^+]_{in} = 0.0476$

For [Cl⁻]:

$100 \times 10^{-3} = -0.0257 \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$-3.981 = \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$0.01867 = \dfrac{120}{[Cl^-]_{in}}$

$[Cl^-]_{in} = \dfrac{120}{0.01867}$

$[Cl^-]_{in} =6427.4$

For [Na⁺]:

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$53.57= \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$[Na^+]_{in}= 2.70$

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Answer:

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