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svetlana [45]
2 years ago
14

PLEASE HELP!!!!!! WILL GIVE BRAINLIEST!!!!!!!!!!

Mathematics
1 answer:
SVEN [57.7K]2 years ago
3 0

Answer:

a) (-9, 4)

b) (0, 0)

c) No

Step-by-step explanation:

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Expression where the solution is 19
MA_775_DIABLO [31]
We want something that equals 19 right? Anything can work here such as
10+9=19 <---we have our outcome as 19 
If you want something more complex 
<span>1(10)+10-1=? 
</span>When you solve that it equals 19! :) 
7 0
2 years ago
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If two ratio are equal they form a ___. I need help IMMEDIATELY. I am going to my grandmas and I need to finish quickly.
Alex17521 [72]

two ratios are equal and form a proportion.

8 0
2 years ago
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A car rental agency has 150 cars. The owner finds that at a price of $48 per day, he can rent all the cars. For each $2 increase
hram777 [196]
Given that for each <span>$2 increase in price, the demand is less and 4 fewer cars are rented.

Let x be the number of $2 increases in price, then the revenue from renting cars is given by
(48 + 2x) \times (150 - 4x)=7,200+108x-8x^2.

Also, given that f</span><span>or each car that is rented, there are routine maintenance costs of $5 per day, then the total cost of renting cars is given by
5(150-4x)=750-20x

Profit is given by revenue - cost.
Thus, the profit from renting cars is given by
</span><span>(7,200+108x-8x^2)-(750-20x)=6,450+128x-8x^2

For maximum profit, the differentiation of the profit function equals zero.
i.e.
</span><span>\frac{d}{dx} (6,450+128x-8x^2)=0 \\  \\ 128-16x=0 \\  \\ x= \frac{128}{16} =8

The price of renting a car is given by 48 + 2x = 48 + 2(8) = 48 + 16 = 64.

Therefore, the </span><span>rental charge will maximize profit is $64.</span>
3 0
3 years ago
During one snowy month a kentucky school held classes 9/11 of possible the school days if there are 22 possible school days how
SOVA2 [1]
This question isn't phrased correctly, but I will assume it's asking about common denominators with fractions.

9/11 1/22

18/22 1/22

18 school days.
5 0
3 years ago
2. Carl needs 15 hours longer than Jennifer to paint a room. If they work together, they can complete the job in 4 hours. Explai
nasty-shy [4]

Answer:

Jennifer would complete the job on her own in 5 hours.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

Rates

The together rate is the sum of their separates rate.

We have that:

Jennifer takes x hours to complete the job on her own, so her rate is 1/x.

Carl needs 15 hours longer than Jennifer, that is, 15 + x hours, so his rate is 1/(15+x).

The together rate is 1/4. So

\frac{1}{4} = \frac{1}{x} + \frac{1}{15+x}

\frac{1}{4} = \frac{15 + x + x}{x(15+x)}

\frac{1}{4} = \frac{15 + 2x}{x(15+x)}

Applying cross multiplication.

x^2 + 15x = 4(15 + 2x)

x^2 + 15x = 60 + 8x

x^2 + 7x - 60 = 0

Quadratic equation with a = 1, b = 7, c = -60. So

\Delta = 7^{2} - 4*1*60 = 289

x_{1} = \frac{-7 + \sqrt{289}}{2} = 5

x_{2} = \frac{-7 - \sqrt{289}}{2} = -12

Since the time to complete the job has to be a positive value.

Jennifer would complete the job on her own in 5 hours.

4 0
2 years ago
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