We will find the inverse of the given functions:
y = x + 2 / x-2
(x-2) y = x + 2
-2y + xy = x + 2
-2y + xy = x + 2
x (y - 1) = 2 + 2y
x (y - 1) = 2 (y + 1)
x = 2 (y + 1) / (y - 1)
f (x) ^ - 1 = 2 (x + 1) / (x - 1)
The inverse is different.
f (x) = x + 1 / x-1
y = x + 1 / x-1
(x-1) y = x + 1
-y + xy = x + 1
x (y - 1) = 1 + y
x (y - 1) = (y + 1)
x = (y + 1) / (y - 1)
f (x) ^ - 1 = (x + 1) / (x - 1)
The inverse is the same.
Answer:
f (x) = x + 1 / x-1
f (x) ^ - 1 = (x + 1) / (x - 1)
f (x) = f (x) ^ - 1
5/4, 1.3, 1 8/25 is ur answer
Answer: False
Systems of linear equations can only have 0, 1, or an infinite number of solutions. These two lines cannot intersect twice. The correct answer is that the system has one solution.
Step-by-step explanation:
The i you normally think of (the one = to sqrt(-1) is not the same i they are using here. They are using this i the same way you would use x = - 1 in any normal equation or relation.
1a + b(-1)
a - b is your answer <<<< answer
Answer:
Attached file
Step-by-step explanation:
