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3 years ago

13

ILL GIVE YOU BRAINLIEST (SMART MATH PERSON!)

1 answer:

MariettaO [177]3 years ago

4 0

Answer:

A - (2a+0)/2 ; (2b+0)/2 = ( a , b )

B - (-2a+0)/2 ; (2b+0)/2 = ( - a, b )

C - (-2a+0)/2 ; ( -2b+0)/2 = ( - a, - b )

D - (2 a+0)/2 ; (-2b+0)/2 = ( a , - b )

Step-by-step explanation:

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A particular rocket is 15 ft tall. A model

m_a_m_a [10]

It’s 5ft that’s litterly the easiest question I have ever seen

6 0

3 years ago

If YV = 28 in, find the length of the major arc VYX. Round to the nearest tenth ( one decimal place).

denpristay [2]

Answer:

$VYX=84.3in$

Step-by-step explanation:

Given

$YV = 28in$

$\angle WZX = 15^\circ$

See attachment

Required

Determine the length of $VYX$

First, calculate the major angle VZX

$\theta = \angle VZX = 360 - \angle WZX$

$\theta = \angle VZX = 360 - 15$

$\theta = \angle VZX = 345$

$\theta = 345$

The length of arc VYX, is:

$L=\frac{\theta}{360} * 2\pi r$

Where

$r = \frac{1}{2} * Diameter$

$r = \frac{1}{2} * YV$

$r = \frac{1}{2} * 28$

$r = 14$

So:

$L=\frac{\theta}{360} * 2\pi r$

$L=\frac{345}{360} * 2 * \frac{22}{7} *14$

$L=\frac{345}{360} * 2 * 22 *2$

$L=\frac{345* 2 * 22 *2}{360}$

$L=\frac{30360}{360}$

$L=84.3in$

Hence, the length of VYX is:

$VYX=84.3in$

7 0

3 years ago

in the rhombus shown below AC and BD are 6 and 4in respectively determine the area of the figure in square inches

bulgar [2K]

The area of a rhombus is computed as follows:

A = p*q*1/2

where p and q are the diagonals of the rhombus.

In this case:

A = AC*BD*1/2

A = 6*4*1/2

A = 12 square inches

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1 year ago

PLS HELP GRADIENT FIRST TO ANSWER GETS BRAINLIEST

irinina [24]

Answer:

Step-by-step explanation:

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2 years ago

Which ordered pair is a solution of the equation shown?<br><br> 25 points

Dahasolnce [82]

Answer:

4y-2 / 3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers