Answer:
a) 0.0082
b) 0.9987
c) 0.9192
d) 0.5000
e) 1
Step-by-step explanation:
The question is concerned with the mean of a sample.
From the central limit theorem we have the formula:

a) 
The area to the left of z=2.40 is 0.9918
The area to the right of z=2.40 is 1-0.9918=0.0082

b) 
The area to the left of z=3.00 is 0.9987

c) The z-value of 1200 is 0
The area to the left of 0 is 0.5

The area to the left of z=1.40 is 0.9192
The probability that the sample mean is between 1200 and 1214 is

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000
e) 
The area to the left of z=-112.65 is 0.
The area to the right of z=-112.65 is 1-0=1
Answer:(-2, 2)
Step-by-step explanation:
7q² - 28 = 0
Add 28 to bothside
7q² - 28 + 28 = 0+ 28
7q² = 28
Divide bothside by 7
7q² / 7 = 28/7
q² = 4
Take the square root of bothside
√q² = ±√4
q = ± 2
q = -2 or q =2
q = (-2, 2)
MachineA: y=120x
MachineA could pack in 12 min
y=120(12)
y=1440
MachineB could pack in 12 min
y=150(12)
y=1800
MachineB pack than MachineA
1800-1440
=360 candies
4-7x= 39
Subtract 4 from both sides
-7x= 35
Divide both sides by -7
x= -5
The value of x+1= (-5)+1= -4.
Commutative property of addition is when 3+9=12 and 9+3=12.