Answer:
not statistically significant at ∝ = 0.05
Step-by-step explanation:
Sample size( n ) = 61
Average for student leader graduates to finish degree ( x') = 4.97 years
std = 1.23
Average for student body = 4.56 years
<u>Determine if the difference between the student leaders and the entire student population is statistically significant at alpha</u>
H0( null hypothesis ) : u = 4.56
Ha : u ≠ 4.56
using test statistic
test statistic ; t = ( x' - u ) / std√ n
= ( 4.97 - 4.56 ) / 1.23 √ 61
= 2.60
let ∝ = 0.05 , critical value = -2.60 + 2.60
Hence we wont fail to accept H0
This shows that the difference between the student leaders and the entire student population is not statistically significant at ∝ = 0.05
Answer:
It would be 10 months for the price of $320.
Step-by-step explanation:
First we need to find how much Anna's swimming charge and Bobie's charge is.
PA=70+t The price of the month equals to the starting fee and monthly charge
120=70+2t The price of 2 months times the monthly charge
50=2t
25=t is Anna's monthly charge
PB=250+t is Bobies starting price and monthly charge
264=250+2t is the month charge for Bobie after 2 months
14=2t
7=t is Bobie's monthly charge
70+25x=250+7x We need to find x which is what month will satisfy both equations
25x=180+7x Subtract 70 from both sides
18x=180 Subtract 7x from both sides
x=10 divide 18 from both sides
Now we have the months that satisfy both equations we need to find the total price that matches with it. So we plug it back into both equations.
PA=70+25x PB=250+7x
PA=70+25(10) PB=250+7(10)
PA=70+250 PB=250+70
PA=320 PB=320
Answer:
207553727590
Step-by-step explanation:
lol lol lol lol lol lol lol
The answer is d hope this helps
The amount of passwords possible is:
Since he only tries once for the first try we get:
Thus there is a:
Chance he will guess the password on his first try.
