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dimaraw [331]
3 years ago
15

A sledgehammer weighs 18 pounds on Earth and 4 pounds on the planet Namar. Which of the following proportions could you use to d

etermine a 100–pound earthling's weight on Namar?
a. 18/4 = 100/w
b. 4/18= w/100
c. 18/4 = w/100
d. both a and b are correct
Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0
18/4 = 100/w
4/18 = w/100

both A and B
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Show all your work to receive full credit for this problem. Solve the system of equations using the elimination method. 2a + 3b
Sindrei [870]

Given equations are;<span>
2a + 3b = -1   ..................equation 1
3a + 5b = -2  ....................equation 2</span>

Now multiply equation 1 with (-3)

The equation will be;

-6a -9b = 3 …………………..equation 3

Now multiply equation 2 with (2)

The equation will be;

6a + 10b = -4 ……………..equation 4

Now add equation 3 and equation 4

-6a – 9b = 3

<span>6a  + 10b = -4</span>

<span>------------------------------</span>

0a + b = -1

b = -1

Now put the value of b in equation 1

2a + 3(-1) = -1

2a -3 = -1

2a = -1+3

2a = 2

a=1

Thus the solution is (a,b) = (1,-1)

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8 0
3 years ago
Can u pls help me with this question ​
luda_lava [24]
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8 0
3 years ago
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A gift box is in the shape of a trapezoidal prism with base lengths of 7 inches and 5 inches and a height of 4 inches. The heigh
jek_recluse [69]
First of all there are multiple formula's to get the volume of a trapezoidal prism:

V=(1/2 * (base1 + base2) * h) * height prism

Using the numbers you gave: 
base1 = 7     base2 = 5     h = 4     height prism = 8

Putting this into the equation:  V=(1/2 * (7 <span>+ 5) * 4) * 8
V= (1/2 * 12 * 4) * 8
V = 24 * 8
V = 192

The volume of the gift box is 191 inches squared.</span>
6 0
3 years ago
Name the quantity measured by each of the seven si base units and give the si symbol of the unit
Nikolay [14]

Answer:

Length , time, mass, current, temperature, amount of mass, luminous intesity

m, sec, kg, A, K, mol, cd

Step-by-step explanation:

Seven basic SI units are used for measurement of

Meter for length

Second for time

Kilogram for mass

Ampere for current

Kelvin for temperature

Mole for amount of mass

Candela for luminous intensity

Symbols of these SI units are

m for meter

sec for second

kg for kilogram

A for ampere

K for kelvin

mol for mole

cd for candela

5 0
3 years ago
Which expression is equivalent to (4g3h2k4)3
RSB [31]

Answer:

d) 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

      \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}    = 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

           =     \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

By using

        (ab)ⁿ = aⁿbⁿ

         \frac{a^{m} }{a^{n} } = a^{m-n}

   =     \frac{(4)^{3} g^{9} h^{6}k^{12} )  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

After simplification , we get

  = 8g^{9}g^{-3} h^{6} h^{-2} k^{12}  - (h^{5} k^{3} )^{5}

 = 8g^{9-3}h^{6-2}  k^{12}  - (h^{5} k^{3} )^{5}

= 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

3 0
3 years ago
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