How do I fill out the table help me answer it but try to explain.

The length of a rectangle is 3 m less than twice the width, and the area of the rectangle is 14 m. Find the dimensions of the re

Rus_ich [418]

Answer:

I just want points so delete this if yiu wantdelete

Step-by-step explanation:

4 0

3 years ago

If (-6,-38) and (5,28) are two anchor points on the trend line, then find the equation of the line

Delicious77 [7]

Answer:

The equation of the line is y = 6x - 2 .

Step-by-step explanation:

Formula for the equation of line is.

$(y - y_{1}) = m (x - x_{1})$

Where m is the slope.

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

As given

If (-6,-38) and (5,28) are two anchor points on the trend line.

Than

$m = \frac{28 - (-38)}{5 - (-6)}$

$m = \frac{28 + 38}{5 + 6}$

$m = \frac{66}{11}$

m = 6

Put the value in the equation of a line.

$(y - (-38)) = 6 (x - (-6))$

$(y + 38) = 6 (x + 6)$

$(y + 38) = 6x + 6\times 6$

$(y + 38) = 6x + 36$

y = 6x +36 - 38

y = 6x - 2

Therefore the equation of the line is y = 6x - 2 .

7 0

3 years ago

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B

jeka94

Answer:

option C is most accurate cause it has a longer neck thus helping in more flexible movements

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.

Contact [7]

A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

$1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \ x\\5^2+10^2 \ \textgreater \ x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x^2 \ \textless \ 125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x \ \textless \ \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \ 10\\ 5^2+x^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}$

$3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \ 10\\ x^2+5^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}$

8 0

3 years ago

Read 2 more answers

Please write it down step by step :)

grandymaker [24]

Answer:

-6

Step-by-step explanation:

Some nasty order of operations coming up.

Firstly, deal with that squared:

-12 / 3 * (-8 + 16 - 6) + 2

Simplify the bracket:

-12 / 3 * 2 + 2

Simplify -12 / 3:

-4 * 2 + 2

Simplify -4 * 2:

-8 + 2

Simplify:

-6

3 0

3 years ago