All categories

3 years ago

What are three expressions equivalent to : 2g+10h?. PLEASE!!!!!

Mathematics

1 answer:

stellarik [79]3 years ago

8 0

Answer:

2(1g + 5h)

(2 x g) + (2 x 5h)

4g + 10h

_______

I don't know the options so I just did 3 possible ways it could be equal

You might be interested in

enrollment in a photography class increased from 25 to 35 students. What was the percent of increase in enrollment?

ElenaW [278]

<u>Answer</u>

40%

<u>Explanation</u>

A parentage value is a value that has been compared to 100.

Percentage = (change in the value)/(the original value) × 100%

= (35-25)/25 × 100%

= 10/25 × 100%

= 40%

6 0

3 years ago

Read 2 more answers

Please help! I need this paper done before my class tomorrow! Thank you!

BabaBlast [244]

Answer:

x=7 and m<LMN = 120

Step-by-step explanation:

if MO bisects LMN then 13x - 31 must be equal to x + 53

13x - x = 53 + 31

12x = 84

x = 7

and

13x - 31 + x + 53 = m<LMN

14x + 22 = m<LMN

since x is 7

14×7 + 22 = 120

3 0

3 years ago

Read 2 more answers

Just part a I’ve done b. <br> Photo provided.

Rasek [7]

Answer:

Step-by-step explanation:

${2}^{x} = \frac{1}{32}$

${2}^{x} = \frac{1}{ {2}^{5} }$

${2}^{x} = {2}^{ - 5}$

$x = - 5$

6 0

2 years ago

I'm getting ripped tonight r.i.p. that (mmm) ayeeeeee

Ede4ka [16]

Ayeee I LOVE THIs song

3 0

2 years ago

Read 2 more answers

What is the simplified form of the following expression? Assume y=0 ^3 sqrt 12x^2/16y

pochemuha

For this case we must simplify the following expression:

$\sqrt [3] {\frac {12x ^ 2} {16y}}$

We rewrite the expression as:

$\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\frac{\sqrt[3]{3x^2}}{\sqrt[3]{4y}}=$

We multiply the numerator and denominator by:

$(\sqrt[3]{4y})^2:\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{\sqrt[3]{4y}*(\sqrt[3]{4y})^2}=$

We use the rule of power $a ^ n * a ^ m = a ^ {n + m}$ in the denominator:

$\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{(\sqrt[3]{4y})^3}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{4y}=$

Move the exponent within the radical:

$\frac{\sqrt[3]{3x^2}*(\sqrt[3]{16y^2}}{4y}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{2^3*(2y^2)}}{4y}=$

$\frac{2\sqrt[3]{3x^2}*(\sqrt[3]{(2y^2)}}{4y}=\\\frac{2\sqrt[3]{6x^2*y^2}}{4y}=$

$\frac{\sqrt[3]{6x^2*y^2}}{2y}$

Answer:

$\frac{\sqrt[3]{6x^2*y^2}}{2y}$

7 0

3 years ago

Read 2 more answers