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Inessa05 [86]
3 years ago
12

10. Simplify r +6 - 3x - 8. F. -2x-2 G. -2x-14 H. -3x-14 I.-3x -2 G-3-8 2x-8

Mathematics
1 answer:
olga2289 [7]3 years ago
5 0
The correct answer is:

I. -3x-2
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kvasek [131]

Answer:

a X=0

b X=0

c X= undetermined

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3 years ago
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Doen's short is 4 times larger than helen's but costs half as much. Deon's shirt costs $9.35.How much is helen's short?
ira [324]

Answer:

4.68

Step-by-step explanation:

D=4h large, 1/2h cost

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Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = t 25 − t2 , [−1, 5]
Zina [86]

Answer: Absolute minimum: f(-1) = -2\sqrt{6}

              Absolute maximum: f(\sqrt{12.5}) = 12.5

Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:

f(t) = t\sqrt{25-t^{2}}

f'(t) = 1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)

f'(t) = \sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }

f'(t) = \frac{25-2t^{2}}{\sqrt{25-t^{2}} } = 0

For this function to be zero, only denominator must be zero:

25-2t^{2} = 0

t = ±\sqrt{2.5}

\sqrt{25-t^{2}} ≠ 0

t = ± 5

Now, evaluate critical points in the given interval.

t = -\sqrt{2.5} and t = - 5 don't exist in the given interval, so their f(x) don't count.

f(t) = t\sqrt{25-t^{2}}

f(-1) = -1\sqrt{25-(-1)^{2}}

f(-1) = -\sqrt{24}

f(-1) = -2\sqrt{6}

f(\sqrt{12.5}) = \sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}

f(\sqrt{12.5}) = 12.5

f(5) = 5\sqrt{25-5^{2}}

f(5) = 0

Therefore, absolute maximum is f(\sqrt{12.5}) = 12.5 and absolute minimum is

f(-1) = -2\sqrt{6}.

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How many oz in 3/4 lbs
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12 ounces-- hope this helps :))

Step-by-step explanation:

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Choose two numbers from the box to complete the sentence.
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Step-by-step explanation:

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