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GREYUIT [131]
3 years ago
5

30 points please help on these questions!

Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:

‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎

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I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT
Nat2105 [25]

Answer:

m∠1 = 67

Step-by-step explanation:

8 0
2 years ago
If u dont know dont worry about it
zhuklara [117]

Answer:

4/15

Step-by-step explanation:

The total number of spins completed is 6+8+7+9 = 30

The letter B came up 8 times

P(B) = number of B's over total

P(B) = 8/30 = 4/15

5 0
3 years ago
My other number is even.its more than 500.my number is?
coldgirl [10]
The answer is sixhunderd
8 0
3 years ago
What do the differences between the points (as shown on the graph) represent?
pishuonlain [190]

Answer:

They represent the rise and run of the graph.

Step-by-step explanation:

The difference between the x-axis of the points represents the "run" of the graph (or how much you should run along x-axis to get to the next point.)

The difference between the y-axis of of the points represents the "rise" of the graph (or how much you should rise up the y-xis to get to the next point).

The ratio of rise to run is the slope of the graph, which tells us  how many steps should we take on the y-axis for every step we move forward on the x-axis.

8 0
3 years ago
A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the
Naya [18.7K]

Answer:

The area is growing at a rate of \frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 \frac{cm}{min} and we identify such as the following differential rate:

\frac{dr}{dt} = 3\,\frac{cm}{min}

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find  \frac{dA}{dt}.

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

A=\pi\,r^2

We now apply the derivative operator with respect to time (\frac{d}{dt}) to this equation, and use chain rule as we find the quadratic form of the radius:

\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}

Now we replace the known values of the rate at which the radius is growing ( \frac{dr}{dt} = 3\,\frac{cm}{min}), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\

which we can round to one decimal place as:

\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

4 0
3 years ago
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