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makkiz [27]
2 years ago
11

Please help answer A and B

Mathematics
1 answer:
Goshia [24]2 years ago
4 0

Answer:

the answer is A

Step-by-step explanation:

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That both (along with the mean) help the data be described the data's spread, which can be the slope if only two points.
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3 years ago
Which equation represents circle C?
OleMash [197]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Select the correct answer from each drop-down menu.
vazorg [7]

Answer:

Step 1: Distribute -2 to 5x and 8

Step 2: Subtract from both sides of the equation 6x

Step 3: Add to both sides of the equation  16

Step 4: Divide both sides of the equation by -16

Step-by-step explanation:

Step 1: Apply the Distributive Property. Then you must  distribute -2 to 5x and 8

Then:

-2(5x+8)=14+6x\\\\-10x-16=14+6x

Step 2: You must apply the Subtraction property of Equality and subtract 6x from both sides of the equation. Then:

-10x-16-6x=14+6x-6x\\\\-16x-16=14

 Step 3: You must apply the Addition property of Equality and add 16 to both sides of the equation. Then:

-16x-16+16=14+16\\\\-16x=30

Step 4: You must apply the Division property of Equality and divide both sides by -16. Then:

\frac{-16x}{-16}=\frac{30}{-16}\\\\x=\frac{30}{-16}\\\\x=-\frac{15}{8}

6 0
3 years ago
Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T
Kaylis [27]

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

6 0
3 years ago
Why did the inequality sign flip?
kumpel [21]

Answer:

We multiplied by a negative number (-8)

We divided by a negative number (-8)

Step-by-step explanation:

Multiplying or dividing both sides of an equation by a negative number changes the inequality of the equation, because it changes the sign of each side of the equation

6 0
2 years ago
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