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ZanzabumX [31]
3 years ago
15

An object has a velocity of 8 m/s and a kinetic energy of 480 J. What is the mass of the object? Formula=1/2mv^2 a(7.5 b(15 kg c

(60 kg d(120 kg
nevermind i found the answer its (15 kg) because to solve for m its m= K2/v squared
Mathematics
2 answers:
sveticcg [70]3 years ago
8 0

Hello!

An object has a velocity of 8 m/s and a kinetic energy of 480 J. What is the mass of the object ?

We have the following data: 

KE (Kinetic Energy) = 480 J

m (mass) = ? (in Kg)

v (speed) = 8 m/s

Formula to calculate kinetic energy:

\boxed{KE = \dfrac{1}{2}*m*v^2}

Solving:

KE = \dfrac{1}{2}*m*v^2

480 = \dfrac{1}{2}*m*8^2

480 = \dfrac{1}{2}*m*64

480*2 = 64*m

960 = 64\:m

64\:m = 960

m = \dfrac{960}{64}

\boxed{\boxed{m = 15\:Kg}}\end{array}}\qquad\checkmark

Answer:  

b) 15 kg

_______________________________

I Hope this helps, greetings ... Dexteright02! =)

SpyIntel [72]3 years ago
7 0
The Kinetic Energy (K.E) of an object can be calculated as:

K.E= \frac{1}{2}mv^{2}

We are given:
K.E = 480 K
Velocity of the object = v = 8 m/s

Using the values, we get:

480= \frac{1}{2}m(8)^{2}  \\  \\ 
480= \frac{1}{2}*64m \\  \\ 
480=32m \\  \\ 
m=15


Thus, the mass of the object will be 15 kg.

So the correct answer is option b
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Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

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The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We assume that the estimated proportion for this case is \hat p =0.5 since we don't have prior information.

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

6 0
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