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Sunny_sXe [5.5K]
3 years ago
11

In ΔCDE, the measure of ∠E=90°, DE = 39 feet, and CD = 89 feet. Find the measure of ∠C to the nearest degree.

Mathematics
2 answers:
Nonamiya [84]3 years ago
8 0
It’s 64.4 :)
i just did it lolz
kolbaska11 [484]3 years ago
4 0

Firstly this shape is an triangle and a triangle has 3 sides/ angles and all angles sum up to 180 degrees...

E = 90 degrees

This explains that it is an hypotenuse triangle so...

answer:

= 39x39 = 1521

= 89x89 = 7921

= 1521 + 7921 = 9442

= square root of 9442 = 97.169954204 rounded off to 97.2

97.2 degrees!

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Please help me still bad at ratio :)
Sholpan [36]

Answer:

111 grams

Step-by-step explanation:

fruit: yoghurt: total

2    : 3           :  2+3=5

The total mass is 185

Divide 185/5 = 37

Multiply each number by 37

fruit: yoghurt: total

2*37    : 3 *37  : 5*37

74            111         185

The mass of the yoghurt is 111

3 0
3 years ago
What is 11,339,800 to the nearest whole number
Bas_tet [7]
11,339,800 is 11,340,000 rounded to the nearest whole number
4 0
3 years ago
Read 2 more answers
the perimeter of a rectangular painting is 304 CM. If the width of the paint is 63 cm what is the length​
s2008m [1.1K]

Answer:

The PERIMETER P is the distance around the rectangle.

Let's call the width of the rectangle W and the length of the rectangle L.

As you go around the edge there two equal lengths and two equal widths.

The formula for the perimeter of a rectangle is P=2*L+2*W.

P=2L%2B2W

Substitute 290 for P and 62 for the width.

290=2L%2B2%2862%29

Solve for L.

290=2L%2B2%2862%29

290=2L%2B124

290-124=2L

2L=166

L=83

The equation L=83 means that the length is 83 cm.

CHECK your work.

2(62)+2(83) = 124+166 = 290cm.

The length of the rectangle is 83cm.

5 0
3 years ago
Select the most specific name for the quadrilateral shown.
ludmilkaskok [199]

Answer:

Square

Step-by-step explanation:

square - (geometry) a plane rectangle with four equal sides and four right angles

6 0
3 years ago
Solve 2x^2 + x - 4 = 0 <br> X2 +
damaskus [11]

Answer:

\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }

Step-by-step explanation:

Hello, please find below my work.

2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0

\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0
3 years ago
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