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VikaD [51]
3 years ago
11

What are the solutions of the equation (2x + 3)2 + 3(2x + 3) + 11 = 02 Use u substitution and the quadratic formula to solve.

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer:

x=-2.4 or x= - 12/5

Step-by-step explanation:

hope that helps.

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Combine any like terms in the expression. If there are no like terms, rewrite the expression.
Llana [10]
If the 3’s were exponents then... i got 50r3

how i solved:

39r3 + 11r3 + 45s3 - 5s3 - 40s3

50r3 + 40s3 - 40s3

50r3 + 0

= 50r3
4 0
3 years ago
An experiment has a single factor with eight groups and five values in each group. a. How many degrees of freedom are there in d
pishuonlain [190]

Answer:

A) 7

B) 32

C) 39

Step-by-step explanation:

Degree of freedom is a means of checking how many values that are free to vary, while using a statistical method.

a) since the experiment has a single factor with eight critical values. Therefore;

C - F = degree of freedom among the group variation

8 - 1 = 7

b) The degree of freedom can be calculated, if the number of data; Therefore, number of data is;

N = 8 × 5 = 40

Then the degree of freedom in determining within group variation,

N - C Therefore;

40 - 8 = 32

C) The degree of freedom in determining the total variation is,

N - 1

40 - 1 = 39

6 0
3 years ago
Find the difference. Write in simplest form.7/8-2/8=
Phantasy [73]
Simple, all you want to do is subtract. 7-2=5; and denominators are not subtracted thus it would be 5/8. And that is the simplest form already 5/8.
7 0
3 years ago
I need help asap please ​
qwelly [4]
The slope is 4/3 because rise over run (if u have heard of that expression)
5 0
3 years ago
From a square piece of cardboard paper of area size 9 m2 , squares of the same size are cut off from each corner of the paper. T
levacccp [35]

Answer:

Max vol = 2 cubic metres

Step-by-step explanation:

Given that from a square piece of cardboard paper of area size 9 m2 , squares of the same size are cut off from each corner of the paper.

Side of the square = 3m

If squares are to be cut from the corners of the cardboard we have the dimensions of the box as

3-2x, 3-2x and x.

Hence x can never be greater than or equal to 1.5

V(x) = Volume = V(x) = x(3-2x)^2\\= 9x+4x^3-12x^2

We use derivative test to find the maxima

V'(x) = 9+12x^2-24x\\V"(x) = 24x-24\\

Equate I derivative to 0

9+12x^2-24x=0\\x=1/2,3/2

If x= 3/2 box will have 0 volume

So this is ignored

V"(1/2) <0

So maximum when x =1/2

Maximum volume

=9(1/2)+4(1/2)^3-12(1/2)^2\\=2 cubic metres

6 0
3 years ago
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