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rjkz [21]
3 years ago
7

Statistics :Q6..........

Mathematics
2 answers:
scZoUnD [109]3 years ago
7 0
I’m thinking A. Would be the most suitable answer for this one
vlada-n [284]3 years ago
6 0
A, and b, are the correct answers! i hope this helps you, and enjoy a meme! best of luck for you! :D

You might be interested in
If a rectangular field has a width of 11 meters and a perimeter of 68 meters calculate the area of the field
Nat2105 [25]
The first step is figuring out the length of the field. To do this, let's work backwards.

We are given the width (11m) and the perimeter (68m). We know that perimeter is measured with the formula P = 2W + 2L or W+W+L+L. All we have to do is plug in our width, 11(2) which is 22, and subtract that from the perimeter:

68 - 22 = 46 < this is the amount of both lengths combined, but in order to find the area, we only need one side. So, divide 46 by 2, and you'll get 23. 

Now the area of a rectangle is found by using A = lw. So plug in your numbers and multiply 23 (length) and 11 (width). You should get 253.

Answer:  253m/D.  
7 0
3 years ago
Read 2 more answers
PLEASE HELP ME....<br><br> Solve for x.<br> 1/4 (x-8)=10
stiks02 [169]

Answer:

x = 48

Step-by-step explanation:

multiply both sides of the equation by 4 to eliminate the fraction

x - 8 = 40 ( add 8 to both sides )

x = 48


6 0
3 years ago
Giving points and brainiest
ziro4ka [17]

Answer:

26

Step-by-step explanation:

you take all sides and add it up

5 0
2 years ago
Are 12/17 and 10/15 equivalent fractions
Sholpan [36]
Nope. because 10/15 can be reduced to 2/3 and 12/17 is in its final form.
5 0
3 years ago
Please help find them <br>1 AB<br><br>2 BC​
spin [16.1K]

Answer:

AB ≈ 15.7 cm, BC ≈ 18.7 cm

Step-by-step explanation:

(1)

Using the Cosine rule in Δ ABD

AB² = 12.4² + 16.5² - (2 × 12.4 × 16.5 × cos64° )

       = 153.76 + 272.25 - (409.2 cos64° )

       = 426.01 - 179.38

       = 246.63 ( take the square root of both sides )

AB = \sqrt{246.63} ≈ 15.7 cm ( to 1 dec. place )

(2)

Calculate ∠ BCD in Δ BCD

∠ BCD = 180° - (53 +  95)° ← angle sum in triangle

∠ BCD = 180° - 148° = 32°

Using the Sine rule in Δ BCD

\frac{BC}{sin53} = \frac{BD}{sin32} = \frac{12.4}{sin32} ( cross- multiply )

BC × sin32° = 12.4 × sin53° ( divide both sides by sin32° )

BC = \frac{12.4sin53}{sin32} ≈ 18.7 cm ( to 1 dec. place )

         

6 0
3 years ago
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