X=8.
Following the similarity statement, we know that AC is to DF as BC is to EF. The ratio would be:
24/(x-2) = 20/5
Cross multiply:
24*5 = 20(x-2)
Use the distributive property:
120 = 20x - 40
Add 40 to both sides:
120+40 = 20x - 40 + 40
160 = 20x
Divide both sides by 20:
160/20 = 20x/20
8 = x
Answer:
19
Step-by-step explanation:
the side is same as 57
what times 3 is 57?
57/3 is 19
AB is 19
pls vote me as brainliest!!!<3
Answer:
Question 4: -11
Question 5: -7
Step-by-step explanation:
Four
Every triangle has 180 degrees.
So all three angles add to 180
<em><u>Equation</u></em>
60 + 80 + x + 51 = 180
<em><u>Solution</u></em>
Combine the like terms on the left. This is the first time I've seen x be a negative value. Almost all of the time it isn't, which should make you wonder.
191 + x = 180
Subtract 191 from both sides.
191 - 191 + x = 180 - 191
x = - 11
Five
If a triangle is a right triangle and one of the angles is 45, then so is the other one.
<em><u>Proof</u></em>
a + 45 + 90 = 180 Combine like terms on the left
a + 135 = 180 Subtract 135 on both sides.
a + 135-135=180-135 Combine the like terms
a = 45
<em><u>Statement</u></em>
That means 52 + x = 45 and here is another negative answer. Subtract 52 from both sides
52 - 52 + x = 45 - 52 Combine like terms.
x = - 7
To find the pre image you need to back track on the image. To get to the image you used (x-6,y+8). Now you need to use the exact opposite to get back to the pre image. For this you would change the signs to look like (x+6,y-8). Now we just apply this to (-4,1).
(-4+6,1-8)
(2,-7) should be the pre image point.
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
