Answer: Option C.
Step-by-step explanation:
The data is:
Destin walked 2km
Jane walked 4000ft.
Let's write both of those in the same units.
The data given is:
1ft = 0.0003048km.
and 4000ft is 4000 times that:
4000ft = 4000*1ft = 4000*0.0003048km = 1.22km
Then if we add those, we get:
Total distance = 2km + 1.22km = 3.22km
So we can already discard option D.
Now, we know that:
1km = 0.6214 miles.
then 3.22 km is 3.22 times that amount:
3.22km = 3.22*1km = 3.22*(0.6214 mi) = 2 miles
The correct option is C.
If you have at least as many equations as your have unknown variables, the 'system' is solvable (unless the equations are copies of eachother).
In this case, isolate one letter and plug it in the other. I'm going for the 2a in the bottom one (it doesn't matter)
2a - 4b = 12 => (divide by two and move the b's to the other side)
a = 6 + 2b. (plug this one into the top equation)
4(6+2b) + 6b = 10 => 24+8b+6b = 10 => 24 + 14b = 10 => 14b = -14 => b=-1
a = 6 + -2 = 4.
So a=4 and b=-1.
Must be in the same units
6 ft/ 24 ft (8yds x 3 = 24 ft)

Let's use yards instead
6 ft = 2 yds
so
2 yds/8 yds again is 1/4
Answer:
6 people would be in each row // It isn't possible for there to be 7 equal rows
Step-by-step explanation:
36 members/6 rows= 6 people per row // 36 members/7 rows= 5.14..... people per row (just doesn't work!)