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vladimir1956 [14]

2 years ago

8

3. Solve: 3(x + 3) > 4(x - 4) A. x > 25 B. x < 25 C. X > - 7 D. x < -7explain

1 answer:

Paha777 [63]2 years ago

7 0

Answer:

B.x<25

Step-by-step explanation:

Let's solve your inequality step-by-step.

3(x+3)>4(x−4)

Step 1: Simplify both sides of the inequality.

3x+9>4x−16

Step 2: Subtract 4x from both sides.

3x+9−4x>4x−16−4x

−x+9>−16

Step 3: Subtract 9 from both sides.

−x+9−9>−16−9

−x>−25

Step 4: Divide both sides by -1.

−x/ −1 > −25/ −1

x<25

Answer:

x<25

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UkoKoshka [18]

Answer: B

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3 0

2 years ago

Find the distance between the two points S (-5,-2) and T (-3,4).

icang [17]

Answer:

$d =2 \sqrt{10}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

<u>Algebra II</u>

Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

<u>Step 1: Define</u>

S (-5, -2)

T (-3, 4)

<u>Step 2: Find distance </u><em><u>d</u></em>

Substitute: $d = \sqrt{(-3+5)^2+(4+2)^2}$
Add: $d = \sqrt{(2)^2+(6)^2}$
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2 years ago

What I 80 multiplied by 2

tresset_1 [31]

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2 years ago

Jessica locates her garden using a coordinate grid with yards as the units. The two points

Oliga [24]

Answer:

These two corners are $\sqrt{13}$ units apart.

Step-by-step explanation:

Distance between two points:

Suppose we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Approximately how far apart are the two corners?

We have to find the distance between the points (-5,-2) and (-8-3). So

$D = \sqrt{(5-(-8))^2+(-2-(-3))^2} = \sqrt{13}$

These two corners are $\sqrt{13}$ units apart.

8 0

2 years ago

The diameter of a cylindrical construction pipe is 6 ft. If the pipe is 34 ft long, what is its volume?

LuckyWell [14K]

Given:

The diameter of the cylindrical pipe = 6ft.

Height of the pipe = 34 ft

To find:

The volume of the pipe.

Solution:

We have,

Diameter of cylinder = 6 ft

Radius of cylinder $=\dfrac{6}{2}=3$ ft

Height of the pipe = 34 ft

Volume of a cylinder is

$V=\pi r^2h$

Where, r is the radius and h is the height.

Putting r=3 and h=34, we get

$V=\pi (3)^2(34)$

$V=\pi (9)(34)$

$V=306\pi$

$V=306(3.14)$

$V=960.84$

Therefore, the volume of the cylindrical pipe is $306\pi \approx 960.84$ cubic ft.

5 0

2 years ago