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olchik [2.2K]
3 years ago
5

Which of the following are ordered pairs for the equation y = 11x + 1?

Mathematics
1 answer:
pishuonlain [190]3 years ago
8 0

Answer:

Step-by-step explanation:

Nfnfnfjjg

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Twice the quantity of 4d increased by 9 is 33.
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A parabola has a vertex of (5,4) and goes through the point (6,-10)
natali 33 [55]
Y = -2(x-5)^2 + 4

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The opposite of the x value of the vertex is h
The y value value of the vertex is k.


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3 years ago
The equation 2x^2 + x - 1 = 0 has two solutions. Find an equation of the form ax^2 + bx + c = 0, which solutions....
leonid [27]

Answer:

Step-by-step explanation:

Let the solution to

2x^2 + x -1 =0

x^2+ (1/2)x -(1/2)

are a and b

Hence a + b = -(1/2) ( minus the coefficient of x )

ab = -1/2 (the constant)

A. We want to have an equation where the roots are a +5 and b+5.

Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.

The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.

So the equation is

x^2-(19/2)x + 22 =0

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B. We want the roots to be 3a and 3b.

Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and

(3a)(3b) = 9(ab) =9(-1/2)=-9/2.

So the equation is

x^2 +(3/2) x -9/2 = 0

2x^2 + 3x -9 =0.

4 0
3 years ago
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