This is how zirconium appears in the periodic table
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235 are the Individual numbers that would expect to have the MN type of genotype.
There are two equations necessary according to Hardy-Weinberg Equilibrium:-
<em>p</em> + q = 1
p² + 2pq + q² = 1
Let,
NN= p
NM=2pq
MM=q
So, according to the question, the frequency of genotype NN is 40%
40% of 500 = Numbers of individuals
Frequency of individuals <em>p </em>= =
Find <em>p</em>² by taking the square root of <em>p</em>.
√(<em>p</em>) = √(0.4)
= 0.632
So, <em>pp + qq = 1 </em>
<em>qq</em> = 1 - <em>pp </em>= 1 - 0.63
q = 0.37
The allele frequencies in the population are known, now finding the frequency of heterozygous genotype.
By Multiplying<em> 2 × p ×q </em>to get heterozygous genotype
<em>2pq = 2 × 0.63 × 0.37` = 0.47</em>
<em>2pq = 0.47</em>
<em>So, 2pq × total population = 0.47 × 500 = 235, NM genotype.</em>
Learn more about Hardy-Weinberg Equilibrium here,
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