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oksano4ka [1.4K]
3 years ago
6

PLS ESTIMATE/ 67% of 8.7

Mathematics
2 answers:
Studentka2010 [4]3 years ago
7 0
67 percent of 8.7

\frac{67}{100}  \times  \frac{x}{8.7}
100x = 67 \times 8.7

100x = 582.9

Divide by 100 on both sides to isolate the x

x = 5.829
Round up (to the nearest tenth place and whole number)

x = 6
x = 5.8
earnstyle [38]3 years ago
5 0

Estimate to me means put away your calculator. Just for stopping you from doing that the exact answer is 5.829

That's not an estimate. An estimate is the approximate answer. 67 % is roughly 67/100 which is very nearly 2/3

2/3 = 0.66666667 so 67/100 = 0.67 is close enough to 2/3

8.7 is close to 9.

So an estimated answer is 2/3 * 9 = 18/3 = 6 and that is close enough.

Every math class you take, you should take an ability to estimate the answers from the class. That is a very important skill. When you are doing a test, you should know if your answers make sense by estimation,

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What should you do to get both numeric terms on the right side of the equation?
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Answer:

you should take the numeric value _16 to right side.

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3 years ago
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The rangers at two park stations spot a signal flare at the same time. Based on the measurements shown in the diagram, what is t
kykrilka [37]

The distance between park station 1 and the point where the flare was set off is 73.9 km.

<h3>What is distance?</h3>

Distance is the length between two points expressed in meters or kilometers.

To calculate the distance between park station 1 and the point where the flare was set off can be calculated using Sine Rule

Formula:

  • a/sinA = b/sinB....................... Equation 1

Where:

  • a = Distance between park station 1 and the point where the flare was set off.

Make a the subject of the equation

  • a = bsinA/sinB............ Equation 2

From the diagram,

Given:

  • A = 59°
  • B = (180-59-75) = 46°
  • b = 6.2 km

Substitute these values into equation 2

  • a = 6.2(sin59°)/(sin46°)
  • a = 73.9 km

Hence, the distance between park station 1 and the point where the flare was set off is 73.9 km.

Learn more about distance here: brainly.com/question/17273444

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5 0
2 years ago
Please help me with the question
mars1129 [50]

(i) The mean is

\displaystyle E(X) = \sum_x x \, P(X = x) \\\\ E(X) = 1\cdot0.175 + 2\cdot0.315 + 3\cdot0.211 + 4\cdot0.092 + 5\cdot0.207 \\\\ \boxed{E(X) = 2.839}

The variance is

V(X) = E((X - E(X))^2) = E(X^2) - E(X)^2

Compute the second moment E(X^2) :

\displaystyle E(X^2) = \sum_x x^2 \, P(X = x) \\\\ E(X) = 1^2\cdot0.175 + 2^2\cdot0.315 + 3^2\times0.211 + 4^2\times0.092 + 5^2\times0.207 \\\\ E(X^2) = 9.997

Then the variance is

\boxed{V(X) \approx 1.9171}

(ii) For a random variable Z=aX+b, where a,b are constants, we have

E(Z) = E(aX+b) = E(aX) + E(b) = a E(X) + b

and

V(Z) = E((aX+b)^2) - E(aX+b)^2 \\\\ V(Z) = E(a^2 X^2 + 2ab X + b^2) - (a E(X) + b)^2 \\\\ V(Z) = a^2 (E(X^2) - E(X)^2) \\\\ V(Z) = a^2 V(X)

Then for Y=\frac{X+3}2, we have

E(Y) = \dfrac12 E(X) + \dfrac32 \\\\ \boxed{E(Y) = 2.918}

E(Y^2) = E\left(\left(\dfrac{X+3}2\right)^2\right) = \dfrac14 E(X^2) + \dfrac32 E(X) + \dfrac94 \\\\ \boxed{E(Y^2) \approx 9.0028}

3 0
2 years ago
$310 phone, 25% discount
VikaD [51]
The discount would be $77.5 as 310 divided by .25 is 77.5.
6 0
2 years ago
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An album was purchased online for 12 dollars, but the company charged a 20% commission for providing it to its customers. How mu
eimsori [14]

Answer:

2.4 dollars

12 x .20 = 2.4

6 0
3 years ago
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