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Genrish500 [490]
3 years ago
13

According to the Guinness Book of World Records, a woman from Russia, Mrs. Vassilyeva, had 69 children between the years 1725 to

1765. She had 16 pairs of twins, 7 sets of triplets, and 4 sets of quadruplets. Suppose one of the births is randomly selected. Given that Mrs. Vassilyeva gave birth to at least 3 children (triplets), what is the probability that she gave birth to quadruplets
Mathematics
1 answer:
Maurinko [17]3 years ago
8 0

Answer:

36.36% probability that she gave birth to quadruplets

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcoes.

Desired outcomes:

Giving births to quadruplets.

She has 4 sets of quadruplets.

So D = 4

Total outcomes:

At least 3 children(triplets).

7 sets of triplets and 4 sets of quadruplets.

So T = 7 + 4 = 11

Probability:

p = \frac{D}{T} = \frac{4}{11} = 0.3636

36.36% probability that she gave birth to quadruplets

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