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rosijanka [135]
3 years ago
14

The length of a rectangle is 3 less than twice the width. If the

Mathematics
2 answers:
faust18 [17]3 years ago
8 0

Answer:

length = 23

breadth = 13

x = 13 , okay

Step-by-step explanation:

see the explanation in attachment.

Gnom [1K]3 years ago
3 0

Answer:

Ihave made it in above pic

1st figure is wrong 2nd is correct

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What is 34 divided by 45
Mrrafil [7]
34 ÷ 45 \frac{34}{45}= 0.7555555555556 ≈ 0.76
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3 years ago
Write an equation of the perpendicular bisector of the segment with the endpoints (8,10) and ( -4,2).
ale4655 [162]

Answer:

The required equation is:

y = -\frac{3}{2}x+9

Step-by-step explanation:

To find the equation of a line, the slope and y-intercept is required.

The slope can be found by finding the slope of given line segment. A the perpendicular bisector of a line is perpendicular to the given line, the product of their slopes will be -1 and it will pass through the mid-point of given line segment.

Given points are:

(x_1,y_1) = (8,10)\\(x_2,y_2) = (-4,2)

We will find the slope of given line segment first

m = \frac{y_2-y_1}{x_2-x_1}\\= \frac{2-10}{-4-8}\\=\frac{-8}{-12}\\=\frac{2}{3}

Let m_1 be the slope of perpendicular bisector then,

m.m_1 = -1\\\frac{2}{3}.m_1 = -1\\m_1 = \frac{-3}{2}

Now the mid-point

(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\= (\frac{8-4}{2} , \frac{10+2}{2})\\=(\frac{4}{2}, \frac{12}{2})\\=(2,6)

We have to find equation of a line with slope -3/2 passing through (2,6)

The equation of line in slope-intercept form is given by:

y = m_1x+b

Putting the value of slope

y= -\frac{3}{2}x+b

Putting the point (2,6) to find the y-intercept

6 = -\frac{3}{2}(2)+b\\6 = -3+b\\b = 6+3 =9

The equation is:

y = -\frac{3}{2}x+9

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3 years ago
What is sandwich theorem?
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3 years ago
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The sum of two numbers is 44, and the larger number is 2 more than the smaller number. What is the smaller number?
leonid [27]

S + L = 44 and L = S +2

6 0
3 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
3 years ago
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