Solve for w:
p = (1.2 w)/h^2
(1.2 w)/h^2 = (6 w)/(5 h^2):
p = (6 w)/(5 h^2)
p = (6 w)/(5 h^2) is equivalent to (6 w)/(5 h^2) = p:
(6 w)/(5 h^2) = p
Multiply both sides by (5 h^2)/6:
Answer: w = (5 h^2 p)/6
Answer:
A, C, E
Step-by-step explanation:
Associative
Commutative
Exponent Property
I think that it the correct answer!
Have a great day/night :)
Answer:
There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.
Step-by-step explanation:
We have these following probabilities:
An 88% probability that the day is cloudy.
An 54% probability that the day is both foggy and cloudy.
What is the probability that a randomly selected day in November will be foggy if it is cloudy?
This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.