3 years ago

What is the value of p(x)=6x^4+2x^3-x+2 at x=0

Mathematics

2 answers:

nasty-shy [4]3 years ago

4 0

Answer:

Step-by-step explanation:

Plug in x=0

p(x)=6x^4+2x^3-x+2 at x=0

p(0)=6(0)^4+2(0)^3-(0)+2

p(0)=2

GrogVix [38]3 years ago

4 0

Answer:

Step-by-step explanation:

6×0^4+2×0^3-0+2

=0+0-0+2

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Step-by-step explanation:

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