3 years ago

What is the value of p(x)=6x^4+2x^3-x+2 at x=0

Mathematics

2 answers:

nasty-shy [4]3 years ago

4 0

Answer:

Step-by-step explanation:

Plug in x=0

p(x)=6x^4+2x^3-x+2 at x=0

p(0)=6(0)^4+2(0)^3-(0)+2

p(0)=2

GrogVix [38]3 years ago

4 0

Answer:

Step-by-step explanation:

6×0^4+2×0^3-0+2

=0+0-0+2

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2 years ago

98-x2=0 solve this with the quadratic formula

Mars2501 [29]

Answer:

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Step-by-step explanation:

$98-x^2=0\\\\-x^2+98=0\\\\a=-1\,,\ \ b=0\,,\ \ c=98\\\\x_1=\dfrac{-0-\sqrt{0^2-4\cdot(-1)\cdot98}}{2\cdot(-1)}=\dfrac{-\sqrt{4\cdot49\cdot2}}{-2}=\dfrac{-2\cdot7\sqrt{2}}{-2}=7\sqrt2\\\\x_2=\dfrac{-0+\sqrt{0^2-4\cdot(-1)\cdot98}}{2\cdot(-1)}=\dfrac{2\cdot7\sqrt{2}}{-2}=-7\sqrt2$