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sleet_krkn [62]
3 years ago
13

Solve the following equation for B be sure to take into account whether a letter is capitalized or not.

Mathematics
2 answers:
const2013 [10]3 years ago
6 0

Answer:

B = <u>d - 3f²</u>

         5M

Step-by-step explanation:

d -3f² = 5 B B

5 BM = d - 3f²

B = <u>d - 3f²</u>

         5M

Ksivusya [100]3 years ago
4 0

Answer:

\huge \boxed{B=\frac{d - 3f^2}{5M}}

\rule[225]{225}{2}

Step-by-step explanation:

d - 3f^2 = 5BM

Dividing both sides by 5M.

\displaystyle \frac{d - 3f^2}{5M} =\frac{5BM}{5M}

\displaystyle \frac{d - 3f^2}{5M} =B

\rule[225]{225}{2}

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Factor the quadratic trinomial x^2-7x+12
tatuchka [14]

Answer:

(x-4)(x-3) hope this helps

Step-by-step explanation:

6 0
3 years ago
The variables A, B, and C represent polynomials where A = x2, B = 3x + 2, and C = x – 3. What is AB – C2 in simplest form?
Bingel [31]
AB - C2 = (x2)(3x + 2) - (x-3)2
AB - C2 = 3x3 + 2x2 - (x2 -6x +9)
AB - C2 = = 3x3 + 2x2 - x2 + 6x - 9
AB - C2 = = 3x3 + x2 + 6x - 9
6 0
3 years ago
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Aaaaaaaaahahahahahqq What’s the answer?
Svetllana [295]

Answer:

2.5

Step-by-step explanation:

-2+5 equals 3-8= -5 divided by 2 equals -2.5

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8 0
3 years ago
URGENT!! NEED THIS IN TWO HOURS. DUMB ANSWERS WILL BE REPORTED ALTHOUGH I UNDERSTAND IF YOU MAKE A SIMPLE MISTAKE IN YOUR CALCUL
Andre45 [30]

Yo sup??

The given points are (1,1),(1,3) and (9,2)

equation of circle is

8x²+8y²+ax+by=0

let us plug in (1,1) in the equation we get

8+8+a+b=0

a+b=-16

let us now plug in (1,3) in the equation

8+8*3²+a+3b=0

a+3b=-80

let us. now solve the two equation in terms of a and b

we get

2b=--64

b=-32

and

a=-16+32

=16

therefore the equation is

8x²+8y²+16x-32y=0

Hope this helps

6 0
3 years ago
7 + 2y = 8x 3x - 2y = 0 Solve the system of equations by substitution. (70/3, 140/9) (7/5, 21/10) no solution coincident
Wittaler [7]
So we have the system of equations:
7+2y=8x equation (1)
3x-2y=0 equation (2)

To use substitution, we are going to solve for one variable in one of our equations, and then we are going to replace that value in the other equation:
Solving for x in equation (2):
3x-2y=0
3x=2y
x= \frac{2}{3}y equation (3)

Replacing equation (3) in equation (1):
7+2y=8x
7+2y=8( \frac{2}{3} y)
7+2y= \frac{16}{3} y
7= \frac{10}{3} y
y= \frac{7}{ \frac{10}{3} }
y= \frac{21}{10} equation (4)

Replacing equation (4) in equation (3):
x= \frac{2}{3}y
x=( \frac{2}{3} )( \frac{21}{10} )
x= \frac{7}{5}

We can conclude that the solution of our system of equations is <span>(7/5, 21/10)</span>
5 0
3 years ago
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