Answer:
V = 255.98189 pi
SA = 172.64114π
Step-by-step explanation:
The first thing to do is find the radius.
the measure of angle AKO = 1/2 the measure of angle AKB
m< AKO = 12.5 degrees
Now use trig to find AO (aka the radius)
tan(12.5) = AO/25
AO = 25* tan(12.5)
<em>I'm leaving it like this to get a more accurate number</em>
Now to find the volume
the volume of a cone is pir^2h/3
plugging everything in we get:
pi(25*tan(12.5))^2 * 25/3
which is about <u>255.98189 pi</u>
Now for surface area
(this is the moment I realize symbols exist)
SA = πr(r+√h²+r²)
plugging everything in we have
π(25tan(12.5))((25tan(12.5)+√625+(25tan(12.5))^2)
<em>I know it looks like a lot but that's mainly because I left the radius as 25tan(12.5)</em>
The Surface Area is about <u>172.64114π</u>
A score of 85 would be 1 standard deviation from the mean, 74. Using the 68-95-99.7 rule, we know that 68% of normally distributed data falls within 1 standard deviation of the mean. This means that 100%-68% = 32% of the data is either higher or lower. 32/2 = 16% of the data will be higher than 1 standard deviation from the mean and 16% of the data will be lower than 1 standard deviation from the mean. This means that 16% of the graduating seniors should have a score above 85%.
X-y=7
y=3x+12|-3x
x-y=7
-3x+y=12
---------------------,-
-2x=19
x=-19/2
