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3 years ago

7

What is -2n-5k+8-4n-11=-7

1 answer:

Fittoniya [83]3 years ago

3 0

Answer:

n= 2/3 - 5/6k , ker

Step-by-step explanation:

-2n-5k+8-4n-11=-7

-6n-5k+8-11=-7

-6n=-7+3+5k

-6n=-4+5k

then divide both sides by -6 to get your answer

n= 2/3 - 5/6k , ker

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Find sin 2a and cot 2a:

geniusboy [140]

Answer:

$sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cot(2\alpha ) = \frac{16511}{18720}$

Step-by-step explanation:

$\text{if } cos(\alpha)=\frac{12}{13}\\\text{That must mean we have a triangle with base 12, and hypotenuse 13.}\\\text{Using Pythagoras, we can determine the base of the triangle must be 5.}\\a^2+b^2=c^2 \text{, where c is the hypotenuse and a, b are the two other sides.}\\c^2-b^2=a^2\\\sqrt{c^2-b^2}=a\\\sqrt{13^2-12^2}=\sqrt{169-144}=\sqrt{25}=5\\\text{Therefore, }sin(\alpha) = \frac{5}{12}\\sin(2\alpha)=2sin(\alpha )cos(\alpha)\\\text{(From double angle formulae identities)}\\$

$sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cos(2\alpha )=cos^2(\alpha)-sin^2(\alpha)\\cos(2\alpha )=(\frac{12}{13})^2-(\frac{5}{12})^2=\frac{16511}{24336}\\cot(2\alpha)=\frac{cos(2\alpha)}{sin(2\alpha)}=\frac{\frac{16511}{24336}}{\frac{10}{13}}=\frac{16511}{18720}$

8 0

3 years ago

Use multiplication to find 2 equivalent fractions to 3/4 and 4/5

Gre4nikov [31]

3/4 = 6/8 = 9/12
4/5 = 8/10 = 12/15

8 0

3 years ago

Read 2 more answers

A sector with a radius of 8 cm has an area of 56pi cm2. What is the central angle measure of the sector in radians?

Maurinko [17]

Answer:

$\frac{7\pi}{4}$ .

Step-by-step explanation:

Given information:

Radius of circle = 8 cm

Area of sector = $56\pi\text{ cm}^2$

Formula for area of sector is

$A=\dfrac{1}{2}\theta r^2$

where, r is radius and $\theta$ is central angle in radian.

Substitute $A=56\pi$ and r=8 in the above formula.

$56\pi=\dfrac{1}{2}\theta (8)^2$

$56\pi=\dfrac{64}{2}\theta$

$56\pi=32\theta$

$\dfrac{56\pi}{32}=\theta$

$\dfrac{7\pi}{4}=\theta$

Therefore, the measure of the sector in radians is $\frac{7\pi}{4}$ .

6 0

3 years ago

The midpoint of \overline{\text{AB}} AB is M(0, -3)M(0,−3). If the coordinates of AA are (2, -5)(2,−5), what are the coordinates

ICE Princess25 [194]

Using the mid-point concept, it is found that the coordinates of B are (-2, -1).

The mid-point of two points is the <u>mean of the coordinates of each point</u>.

In this problem:

The points are: A(2, -5) and B(x,y).

The mid-point is (0, -3).

Applying the concept for both the x and y-coordinates, we have that:

$\frac{x + 2}{2} = 0$

$x + 2 = 0$

$x = -2$

$\frac{-5 + y}{2} = -3$

$-5 + y = -6$

$y = -1$

The coordinates of B are (-2, -1).

To learn more about the mid-point concept, you can take a look at brainly.com/question/10956693

5 0

2 years ago

Joel needs to buy some blank DVDS and zip disks to back up a large amount of data that has been generated by an accounting firm.

wlad13 [49]

Answer:

D = 4, Z = 24

Step-by-step explanation:

6D+3Z = 96

5D+4Z = 116

multiply top by 5 and bottom by -6

top equation = 30D+15Z = 480

bottom equation = -30D-24Z = -696

Cancel 30D and -30 D

top equation = 15Z = 480

Bottom equation = -24Z = -696

15Z - 24 Z = 480 - 696

-9Z = 216

Z = 216/9

Z = 24

Now that we have the value of Z, we can substitute it in any equation to find D

6D + 3(24) = 96

6D + 72 = 96

6D = 96 - 72

6D = 24

D = 24/6

D = 4

4 0

3 years ago