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lora16 [44]
3 years ago
14

PLEASE ANSWER THIS AND IF YOU DO YOU GET 1. FOLLOW 2. BRAINLIEST

Mathematics
1 answer:
snow_lady [41]3 years ago
7 0
First: 0
Second: 0
Third: -5
Fourth: y=4x
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Fynjy0 [20]

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its the middle one

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had this on a test, got it right

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What is the standard form equation of an ellipse that has vertices (18,1) and (−10,1) and co-vertices (4,14) and (4,−12)?
viktelen [127]

Answer: \frac{(x-4)^2}{196} +\frac{(y-1)^1}{169} =1

Step-by-step explanation:

You first need to determine if the ellipse is horizontal or vertical, which can be found by the length of the major axis.

The vertices are at (18,1) and (-10,1). The distance is 28 units.  (horiz)

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The center is at (4,1)

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The minor axis is 2b, so b would e 26/2=13 squared: 169

Inserting the center and a,b values into the standard form eq:

\frac{(x-4)^2}{196} +\frac{(y-1)^1}{169} =1

hope this helps.

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1 year ago
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rosijanka [135]

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Step-by-step explanation:

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Step-by-step explanation:

Graph the following points:

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