Question

If a dart board was thrown randomly at the dartboard shown below, what is the probability that it will land in the bull’s-eye? The radius of the bull’s-eye is 2 cm, the radius of the middle circle is 8 cm, and the radius of the outer circle is 14cm.

Answer 1

Answer:

Correct option: C -> 2%

Step-by-step explanation:

To find this probability we just need to divide the area of the bull's-eye circle by the total area of the outer circle.

The area of a circle is given by the equation:

$area = \pi * radius^2$

The outer radius is 14 cm, so:

$outer\ area = \pi * 14^2 = 196\pi\ cm^2$

The inner radius is 2 cm, so:

$inner\ area = \pi * 2^2 = 4\pi\ cm^2$

So the probability is:

$inner\ area / outer\ area = 4\pi / 196\pi = 0.02 = 2\%$

Correct option: C