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BARSIC [14]
2 years ago
5

Write the sentence as an equation. the quotient of 331 and u is the same as 13

Mathematics
2 answers:
umka2103 [35]2 years ago
6 0
331 dived by u equals 13
snow_tiger [21]2 years ago
3 0
331(divide sign)u=13
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SOMEBODYY HELP ILL GIVE BRAINLYY......
ANTONII [103]

Step-by-step explanation:

a^2+b^2 = c^2

C is the biggest number, so put in all the numbers in the equation then if it's equal then it's a right triangle.

example: 6^2 + 8^2 = 10^2

36 + 64 = 100

100 = 100

this one is a right angle because the two sides is equal to the hypotenuse(largest number).

3 0
2 years ago
What is the solution of the system?y=-8x-2 and y=-6x+4
Tcecarenko [31]
Hello : 
<span>y=-8x-2 and y=-6x+4
-8x-2 = -6x +4
-8x+6x =2+4
-2x =6
x = - 3
y = -6(-3)+4 =22</span>
8 0
3 years ago
Hi, the answer is K but can anyone show why
dlinn [17]

Let's do 51 and 52.

51. The contrapositive has the same truth value as the original statement. That's opposed to the converse, which may or may not be true independent of the original statement.

The contrapositive of IF P THEN Q is IF not Q THEN not P.  They're equivalent.  Here that's If the cat is not female then it is not tricolor.

Answer: C

52.  

(x^3)^{(4-b^2)}=1

x^{3(4-b^2)} = 1

For the statement to be true, the exponent must be zero:

3(4-b^2) = 0

b^2 = 4

b = \pm 2

Both positive 2 and negative 2 have a square of 4.

Answer: K

By the way, usually we assume 0^0=1 so the restriction that x \ne 0 isn't really necessary.  Think of the definition of a polynomial or the binomial expansion:

\displaystyle f(x)=\sum_{k=0}^n a_k x^k

\displaystyle(x+y)^n=\sum_{k=0}^n {n \choose k} x^{k}y^{n-k}

For these common equalities to work when x=0 we need to define 0^0=1


3 0
3 years ago
What transformation was not done to the linear parent function, f(x) = x, to
Butoxors [25]

Answer:

C.

Step-by-step explanation:

The function shifted <em>left</em> five units instead of <em>right</em> five units.

There's no vertical compression in the equation provided, but that's probably just a typo since there's a random bracket that I assume was supposed to be a fraction.

7 0
2 years ago
When x=3, y=16 and when x=6, y=8. Which inverse variation equation can be used to model this function
MakcuM [25]

Inverse variation equations take the following form:

y = a/x, where a is some constant

We know x=3, y=16 and x=6, y=8 satisfy the equation.

Let's find the value of a.

16=a/3

Multiply both sides by 3

16*3 = a

48 = a

Thus, the equation is:

y = 48/x

You can use the other values of x and y to test, but I'm sure this is the correct equation. :)

(This answer was sent on mobile, so please pardon any spelling errors I may have)

8 0
3 years ago
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