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goblinko [34]
3 years ago
7

The local ranger station tracked and tagged 2,844 adult female black bears in a national park. A random sample of 9 adult female

black bears from those tagged had an average body weight of 203 pounds with standard deviation 25 pounds. Which of the following is a point estimate for the population mean weight of all female black bears that are tagged?
a. 9
b. 25/√9
c. 25
d. 203
e. 2,844
Mathematics
1 answer:
Phantasy [73]3 years ago
8 0

Answer:

203

Step-by-step explanation:

Sample size, n = 9

Mean weight, m = 203

Standard deviation = 25

Point estimate for the population mean weight of all black bears that are tagged `

The point estimate of the population mean ;

ΣX / n

Sum of sample / sample size ;

This is the mean value formula for the sample.

However, since it has been given in the question that, sample mean weight value = 203 ; then the point estimate of the population mean weight = 203

You might be interested in
(50 Points Please help)
Elina [12.6K]

Answer:

A. Length of a Tour Bus                       ↔     #2.      1.1 × 10¹ meters

B. Width of an apple                             ↔      #3.     4 × 10⁰ centimeters

C. Distance from Earth to a Satellite    ↔    #6.     8 × 10² kilometers

D. Thickness of a human hair               ↔     #5.      9 × 10¹ micrometers

Step-by-step explanation:

The length of a tour bus should be measured in meters. It sure is way less than 1 kilometer and way more than a few centimeters. It could be about some meters, more than 5 meters, may be between 10 meters and 15 meters.

The measurement in the box # 2. is 1.1 × 10¹ meters, which is equivalent to 1.1 × 10 meters = 11 meters. Thus, this is a reasonable length.

B. Width of an apple.  

The most appropriate unit to measure the width of an apple should be centimeter. It certainly is shorter than 1 meter and bigger than 1 mm.

The width of an apple could be, more or less, around 8 centimeters. The only measurement in the boxes that is in that order is that in the box #3., 4 × 10⁰ centimeters, because 10⁰ = 1, so 4 × 10⁰ = 4 × 1 = 4 centimeters.

C. Distance from Earth to a Satellite

The distance from Earth to a satellite should be measured in kilometers.

You can find in the internet that the distances of the satellites are between 700 kilometers and 36,000 kilometers.

The number in the box #1 is too big, in the order of ten trillions of kilometers, because one trillion is 10¹²; thus that is nonseasonal (too big).

The number in the box #6 is  8 × 10² kilometers, which is equal to 8 × 100 = 800 kilometers.

Thus,  8 × 10² kilometers (box #6) is the most reasonable measurement for the distance from Earth to a Satellite

D. Thickness of a human hair

Of course, kilometers, meters, centimeters and even millimeters are units too big to measure the thickness of a human hair.

One micrometer is 10⁻⁶ meters or 10⁻³ millimeters.

In the internet you can find that diameter of the human hair is in the range from 17 micrometers to 181 micrometers.

The measurement in the box #5. is 9 × 10¹ micrometers, which is equivalent to 9 × 10 = 90 micrometers.

Thus, 9 × 10¹ micrometers is the most reasonable measurement for the thickness of a human hair.

5 0
3 years ago
Read 2 more answers
PLZ HELP, WILL MARK BRAINLIEST
andreev551 [17]

220.5

i dont know how to show my work sorry :) hope it helps

3 0
3 years ago
Assume that the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. If th
ioda

Answer:

The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 69.0 inches and a standard deviation of 2.8 inches.

This means that \mu = 69, \sigma = 2.8

What is the bottom cutoff heights to be eligible for this experiment?

The bottom 15% are excluded, so the bottom cutoff is the 15th percentile, which is X when Z has a pvalue of 0.15. So X when Z = -1.037.

Z = \frac{X - \mu}{\sigma}

-1.037 = \frac{X - 69}{2.8}

X - 69 = -1.037*2.8

X = 66.1

The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

8 0
3 years ago
PLEASES HELP ME OUT ON THIS
ki77a [65]
The answer is d:11.
3 0
3 years ago
Read 2 more answers
The sum of a number and its square is 72. Find the number
Vladimir79 [104]
The answer is 8. 8 squared is 64 plus 8 is 72
7 0
3 years ago
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