I believe it’s D not 100% sure but yea
Answer:
Yes
Step-by-step explanation:
2•44=88
4•22=88
8•11=88
Answer:
Step-by-step explanation:
yes
he had 150.
Step-by-step explanation:
i cant explain
Answer:
0.3907
Step-by-step explanation:
We are given that 36% of adults questioned reported that their health was excellent.
Probability of good health = 0.36
Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.
Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.
i.e. ![P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)](https://tex.z-dn.net/?f=P%28x%5Cleq%203%29%3DP%28x%3D1%29%2B%7BP%28x%3D2%29%2BP%28x%3D3%29)
Formula :![P(x=r)=^nC_r p^r q ^ {n-r}](https://tex.z-dn.net/?f=P%28x%3Dr%29%3D%5EnC_r%20p%5Er%20q%20%5E%20%7Bn-r%7D)
p is the probability of success i.e. p = 0.36
q = probability of failure = 1- 0.36 = 0.64
n = 11
So, ![P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)](https://tex.z-dn.net/?f=P%28x%5Cleq%203%29%3DP%28x%3D1%29%2B%7BP%28x%3D2%29%2BP%28x%3D3%29)
![P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}](https://tex.z-dn.net/?f=P%28x%5Cleq%203%29%3D%5E%7B11%7DC_1%20%280.36%29%5E1%20%280.64%29%5E%7B11-1%7D%2B%5E%7B11%7DC_2%20%280.36%29%5E2%20%280.64%29%5E%7B11-2%7D%2B%5E%7B11%7DC_3%20%280.36%29%5E3%20%280.64%29%5E%7B11-3%7D)
![P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}](https://tex.z-dn.net/?f=P%28x%5Cleq%203%29%3D%5Cfrac%7B11%21%7D%7B1%21%2811-1%29%21%7D%20%280.36%29%5E1%20%280.64%29%5E%7B11-1%7D%2B%5Cfrac%7B11%21%7D%7B2%21%2811-2%29%21%7D%20%20%280.36%29%5E2%20%280.64%29%5E%7B11-2%7D%2B%5Cfrac%7B11%21%7D%7B3%21%2811-3%29%21%7D%20%280.36%29%5E3%20%280.64%29%5E%7B11-3%7D)
![P(x\leq 3)=0.390748](https://tex.z-dn.net/?f=P%28x%5Cleq%203%29%3D0.390748)
Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907