Question

suppose two soccer teams consist of players with a combined average height of 66 inches. if team a has an average height of 68 inches and has twice as many members as team b, what is the average height of team b

Answer 1

Answer:

The average height of team b is 62 inches.

Step-by-step explanation:

Mean:

The mean of a data-set is the sum of all values in the data-set divided by the number of values, that is:

$M = \frac{s}{n}$

Sum:

Team a: Mean of 68 inches, 2x members.

Team b: Mean of y inches, x members.

So

$s = 68*2x + yx = x(136 + y)$

Number of athletes:

$n = 2x + x = 3x$

What is the average height of team b?

$66 = \frac{x(136+y)}{3x}$

$66 = \frac{136 + y}{3}$

$136 + y = 198$

$y = 198 - 136 = 62$

The average height of team b is 62 inches.