Answer:
10.5618feet, 0.8125sec
Step-by-step explanation:
Given the height reached by the catapult expressed by the equation H=-16T^2+26T
At the maximum height, the velocity of the object is zero, hence;
v = dh/dt = 0
-32t + 26 = 0
-32t = -26
t = 26/32
t = 0.8125secs
Hence it will attain the maximum height after 0.8125second
Substitute t = 0.8125s into the expression to get the maximum height
H=-16t^2+26t
H = -16(0.8125)^2 + 26(0.8125)
H = -16(0.6602) + 21.125
H = -10.5632+21.125
H = 10.5618
hence the maximum height reached by the ball is 10.5618feet
The answer is A. 14 and 15
Answer:
537.47712
Step-by-step explanation:
a = 125 ... the first term?
r = 1.2
ok use the formula: a_n = (a_1) * r ^(n-1)
we want a_9 = (a_1) * r^(9-1)
a_9 = 125 * (1.2)^8 = 125 * 4.29981696 = 537.47712
Whole number because it’s not the others
Answer:
1/4+1/4+1/4+1/4+1/4+1/4= 1.5
3/10x2/3= 0.2
2/4x2/3= 0.33333333333 (just put 0.3 with a line on top of the 3)
6 divided by 1/2 = 12/1 or 12
9 divided by 1/3 = 27/1 or 27
2/5 divided by 3/4 = 8/15
1/2 divided by 2/3 = 3/4
