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Marrrta [24]
3 years ago
6

Find two expressions whose difference is 3x + 4​

Mathematics
1 answer:
anastassius [24]3 years ago
3 0

Answer:

(7x+4) and (4x)

Step-by-step explanation:

The expression are (7x+4) and (4x)

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5/9 
5 times 4= 20
12 times 3=36
20/36=5/9
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3 years ago
Steven wishes to save for his retirement by depositing $2,000 at the beginning of each year for thirty years. Exactly one year a
Ad libitum [116K]

Step-by-step explanation:

i = interest 3% for 30 years

This is a simple dynamical system for whom the the solutions are given as

S=R[\frac{(i+1)^n-1}{i}](i+1)

putting values we get

S=2000[\frac{(1.03)^{30}-1}{0.03}](1.03)

= $98005.35

withdrawal of money takes place from one year after last payment

To determine the result we use the present value formula of an annuity date

P = R\frac{1-(1+i)^{-n}}{i}{i+1}

we need to calculate R so putting the values and solving for R we get

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3 years ago
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3 years ago
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Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x
iren [92.7K]

Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

Step-by-step explanation:

One is asked to find the root of the following equation:

2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

2x^2-5x+1=0

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

\frac{5(+-)\sqrt{17}}{4}

Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

8 0
3 years ago
Where should she place the top-left corner of the left-most plaque? 9feet high 11 feet wide 6in of space 2 wide
labwork [276]

Answer:

78

Step-by-step explanation:

8 0
3 years ago
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