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Marrrta [24]
2 years ago
6

Find two expressions whose difference is 3x + 4​

Mathematics
1 answer:
anastassius [24]2 years ago
3 0

Answer:

(7x+4) and (4x)

Step-by-step explanation:

The expression are (7x+4) and (4x)

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A circle of radius of 4 inches has an arc length of 5.8 inches. Find the measure of the central angle.
kondor19780726 [428]
<h3>SOLUTION : </h3>

The radius of the circle is 4 inch and has an arc length of 5.8 inches . We know that if the central angle is 360° then the arc length is 2\pi r . Similarly when angle is theta ,

\implies Arc = radius \times \theta

Now substitute respective values , from the given data ,

\implies 5.8 inch = 4inch * \theta \\\\\implies 0.14 m = 0.1 * \theta \\\\\implies \boxed{\red{\theta \approx 1.4 \ rad }}

This is our required answer!

4 0
3 years ago
The area of a trapezoid is 69.6 in2 and its altitude is 8.7 in. Find the perimeter of the trapezoid if the sum of its legs is eq
BaLLatris [955]
1. To solve this problem, you must apply the formula for calculate the area of the trapezoid, which is:
 
 A=(B+b)h/2
 
 A is the area of the trapezoid (A=69.6 in²).
 (B+b) is the sum of the bases of the trapezoid.
 h is the height of the trapezoid (h=8.7 in).
 
 2. When you clear the sum of the bases (B+b), you have:
 
 A=(B+b)h/2
 2A=<span>(B+b)h
</span><span> (B+b)=2A/h
</span> (B+b)=2(69.6 in²)/(8.7 in)
 (B+b)=16 in
 
 3. The problem says that <span>the sum of its legs is equal to the sum of its bases, therefore, the perimeter is:
</span> 
 Sum of the legs=Sum of the bases (B+b)=16 in
 
 Perimeter=16 in+16 in
 Perimeter=32 in
7 0
3 years ago
Read 2 more answers
Please help me :( pls help
Serggg [28]

Answer:

See below for an explanation

Step-by-step explanation:

I'm unsure of your answer choices, so I'll show you how to solve for the remainder of the whole triangle:

Since we are given a hypotenuse of 5 and a side length of 4 which is adjacent to ∅, the trig function to solve for ∅ would be cosine because cos∅=adjacent/hypotenuse (SOHCAHTOA). This means cos∅=4/5 and taking the arccos (the inverse of cosine aka. cos^-1) of both sides gets us ∅=36.87°

Side AC can be solved by using the Pythagorean Theorem since a²+b²=c² can be turned into 4²+b²=5². We would then have 16+b²=25 which is also b²=9, thus taking the square root of both sides gives us b=3 (since distance is positive). Thus, side AC has a length of 3 units.

∠A can be found by using the Triangle Angle-Sum Theorem. Since all the interior angles of a triangle must add up to 180°, then ∠A+∠B+∠C=180°. We know that since ∠B=36.87° and ∠C=90°, then we have the equation ∠A+36.87°+90°=180°. Combining like terms on the left side gets us ∠A+126.87°=180° and subtracting on both sides get us ∠A=53.13°

<u>Final sides and angles of the triangle:</u>

∠A=53.13°

∠B=36.87°

∠C=90°

BC=4

BA=5

AC=3

3 0
3 years ago
Simplify the equation : 14/ 5 - 1/4​
asambeis [7]

Answer:

51/20

Explanation:

14/5-1/4=

14*4/5*4-1*5/4*5=

56/20-5/20=

56-5/20=

51/20

8 0
2 years ago
Twenty-seven marbles are shared
sladkih [1.3K]

Answer:

4

Step-by-step explanation:

27-6=21     1

21-6=15      2

15-6=9       3

9-6=3        4

5 0
1 year ago
Read 2 more answers
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