The last option is the correct answer
Answer:
0.405 or 40.5%
Step-by-step explanation:
Let event A=having a periodontal disease
event B=having a heart attack
we are given
P(A)=P(having a periodontal disease)=0.30
P(B)=P(having a heart attack)=0.15
P(A/B)=P(have a periodontal disease/have a heart attack)=0.81
P(B/A)=P(have a heart attack/have a periodontal disease)=?
P(A/B)=P(A∩B)/P(B)
P(A∩B)=P(B)*P(A/B)=0.15*0.81=0.1215
P(B/A)=P(A∩B)/P(A)=0.1215/0.3=0.405
There is 40.5% probability that if someone has periodontal disease will have a heart attack.
Answer:
C=15
Step-by-step explanation:
times 1.5 and 10 to get 15 then divide by 1 to get C equals 15
