3 years ago

Please help mee What is the smallest positive integer whose proper divisors add up to more than the integer itself?

Mathematics

1 answer:

Law Incorporation [45]3 years ago

8 0

Answer:

Step-by-step explanation:

The proper divisors of 12 are

1 2 3 4 6

Add those together you get 16

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VashaNatasha [74]

Answer:

Step-by-step explanation:

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3 years ago

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How do you solve that?

Aleks [24]

Put it in the form

ax^2 + bx + c = 0

use the quadratic formula

x = [ -b + sqrt( b^2 - 4 ac ) ] / 2a

x = [ -b - sqrt( b^2 - 4 ac ) ] / 2a

7v^2 - 7v - 22 = 0

a = 7
b = -7
c = -22

v = [ 7 + sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = 2.34

v = [ 7 - sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = -1.34

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yaroslaw [1]

Answer:

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Step-by-step explanation:

i think this is right

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