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2 years ago

Please help mee What is the smallest positive integer whose proper divisors add up to more than the integer itself?

Mathematics

1 answer:

Law Incorporation [45]2 years ago

8 0

Answer:

Step-by-step explanation:

The proper divisors of 12 are

1 2 3 4 6

Add those together you get 16

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In the data set shown below, what is the value of the quartiles? {42, 43, 44, 44, 48, 49, 50} A. Q1 = 43.5; Q2 = 44; Q3 = 49 B.

ANTONII [103]

Answer:

Step-by-step explanation:

I don't actually know how to explain it but,

Q1=43.5

Q2=44

Q3=48.5

Sorry, I can't help more.

3 0

3 years ago

EXPAND:

Sladkaya [172]

Answer:

$\displaystyle A) 5\log( {x}^{} ) + 2 \log( {y}^{} )$

Step-by-step explanation:

we would like to expand the following logarithmic expression:

$\displaystyle \log( {x}^{5} {y}^{2} )$

remember the multiplication logarithmic indentity given by:

$\displaystyle \rm \log( \alpha \times \beta ) \iff \log( \alpha ) + \log( \beta )$

so our given expression should be

$\displaystyle \log( {x}^{5} ) + \log( {y}^{2} )$

by exponent logarithmic property we acquire:

$\displaystyle 5\log( {x}^{} ) + 2 \log( {y}^{} )$

hence, our answer is A

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=if%20%5C%3A%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%29%5E%7B6%7D%20%20%5Ctimes%20%28%20%5Cfrac%7B16%7

zhenek [66]

Answer:

Step-by-step explanation:

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{x+2}$

$\frac{3^6}{4^6} \cdot \frac{16^5}{9^5}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{4^6} \cdot \frac{(4^2)^5}{(3^2)^5}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{4^6} \cdot \frac{4^{10}}{3^{10}}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{3^{10}} \cdot \frac{4^{10}}{4^6}=\frac{4^{x+2}}{3^{x+2}}$

$3^{-4} \cdot 4^{4}=4^{x+2}3^{-(x+2)}$

This implies

x+2=4

and

-(x+2)=-4.

x+2=4 implies x=2 since subtract 2 on both sides gives us x=2.

Solving -(x+2)=-4 should give us the same value.

Multiply both sides by -1:

x+2=4

It is the same equation as the other.

You will get x=2 either way.

Let's check:

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{2+2}$

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{4}$

Put both sides into your calculator and see if you get the same thing on both sides:

Left hand side gives 256/81.

Right hand side gives 256/81.

Both side are indeed the same for x=2.

4 0

3 years ago

16 increased by twice a munber is -24

dangina [55]

We can form this algebraic equation to work the equation out:

16 + 2x = -24
2x = -40
x - 20

Hope I helped.

8 0

3 years ago

5) One restaurant charges $7 per person and $1 admission fee. A second compant Charges $5 per

Assoli18 [71]

The people will there need to be in order for the second company to be less expensive in 1st restaurant.

Always assume the unknowns are variables when attempting to find them, and then construct the equation using the parameters specified in the question.

Admission fee for 1st restaurant = $1

Charge for 1st restaurant per person = $7

Admission fee for 2nd restaurant = $15

The number of employees required for 2nd restaurant need to have in order to be less expensive = x

Total amount needed for 1st restaurant = $1 + $7 = $8

To make the 2nd restaurant less expensive =

As the total amount of 1st restaurant is $8 and the admission fee 2nd restaurant itself is $15 2nd restaurant is more expensive than the 1st one.

To learn more about Word problems related to arithmetic operation from the link:

brainly.com/question/24464054

#SPJ9

5 0

1 year ago