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Naddik [55]
2 years ago
15

Please help UwU also hope your day is going GREAT >w

Mathematics
2 answers:
Dvinal [7]2 years ago
7 0

Answer:

B is the answer for the question

Gelneren [198K]2 years ago
5 0

B IS YOUR ANSWER LOL.

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Factor: 81y^2-49<br> Your answer
oksian1 [2.3K]

Answer:(9y-7)(9y+7)

Step-by-step explanation:

81y^2-49

=(9y)^2-(7)^2

=(9y-7)(9y+7)

4 0
2 years ago
CAN SOMEBODY HELP ME WITH THIS PROBLEM PLZZZ
kvv77 [185]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
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You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
koban [17]

Answer:

a) No, because the probabilities of winning the 2nd game are dependant on the result of the 1st game. The probabilities are different if you win or lose the first game.

b) P=0.42

c) P=0.08

d)

X    |    P(X)

------------------

0    |    0.42

1     |    0.50

2    |    0.08

e) E(x)=0.66

s.d.=0.62

Step-by-step explanation:

a) No, because the probabilities of winning the 2nd game are dependant on the result of the 1st game. The probabilities are different if you win or lose the first game.

b) The probability of losing the first game is

P(G_1=L)=1-P(G_1=W)=1-0.4=0.6

The probability of losing the second game, given that the first game was lost is:

P(G_2=L|G_1=L)=1-P(G_2=W|G_1=L)=1-0.3=0.7

So the probability of losing both games is:

P(G_2=L\&G_1=L)=P(G_1=L)*P(G_2=L|G_1=L)=0.6*0.7=0.42

c) The probability of winning both games is:

P(G_2=W\&G_1=W)=P(G_1=W)*P(G_2=W|G_1=W)=0.4*0.2=0.08

d) The variable X can take values 0, 1 and 2.

X=0 is when both games are lost. This happens with probability P=0.42.

X=2 is when both games are won. This happens with probability P=0.08.

X=1 is when one game is won and the other is lost. This happens with probability P=1-0.42-0.08=0.50.

Then the table of probabilities become:

X    |    P(X)

------------------

0    |    0.42

1     |    0.50

2    |    0.08

e) The expected value is:

E(x)=\sum p_ix_i=0.42*0+0.50*1+0.08*2=0.00+0.50+0.16=0.66

The variance and standard deviation of x are:

V(x)=\sum p_i(x_i-E(x))^2\\\\V(x)=0.42(0-0.66)^2+0.50(1-0.66)^2+0.08(2-0.66)^2\\\\V(x)=0.42*0.4356+0.50*0.1156+0.08*1.7956\\\\V(x)=0.183+0.058+0.144=0.385\\\\\\\sigma=\sqrt{V(x)}=\sqrt{0.385}=0.62

The standard deviation can

5 0
3 years ago
What is the sum of 3.6 X 10^3 and 6.1 X 10^3
Allisa [31]
3.6 × 10³ + 6.1 × 10³

(3.6 + 6.1) × 10³

<span>9.7 × 10³
</span>
5 0
3 years ago
What is the SECOND STEP to solve this equation?
Andre45 [30]

Answer:

Step-by-step explanation:

subtract 2 from both sides

7 0
2 years ago
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