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fenix001 [56]
3 years ago
9

Deposition does NOT occur

Mathematics
2 answers:
zmey [24]3 years ago
5 0
I think it’s A. But not sure
Vitek1552 [10]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Not A because it has rocks in it

Not B because thats clear

Not C same reason for B

Yes D because it dissolves

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Pre-Calculus - Systems of Equations with 3 Variables please show work/steps
inessss [21]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0
3 years ago
Solve for x in the given interval.
Nat2105 [25]

Answer:

7pi/2

Step-by-step explanation:

Given the expression cosec x = -1

I'm trigonometry csecx = 1/sinx

The equation becomes

1/sin(x) = -1

Sinx = -1

x = arcsin(-1)

x = -90°

x is negative in the third and 4th interval

Third interval;

x = 180+90

x = 270°

x = 3pi/2

Since the angle should be within 3pi < x < 4pi

Add 2pi to the angle

x = 2pi+ 3pi/2

x = 7pi/2

Hence the required angle is 7pi/2

8 0
3 years ago
Given that f(x) = x2 + 12x + 35 and g(x) = x + 7, find (f:g)(x) and express
rusak2 [61]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
218 rounded to nearest 10
tangare [24]
The answer is 220 because you would just have to round 1 to 2 than everytging behind it is a zero
4 0
3 years ago
Read 2 more answers
Subtract (r - 3q + 5p) - (-4r - 3q - 8p)
Alex787 [66]

Answer: ok so Let's simplify step-by-step.

r−3q+5p−(−4r−3q−8p)

Distribute the Negative Sign:

=r−3q+5p+−1(−4r−3q−8p)

=r+−3q+5p+−1(−4r)+−1(−3q)+−1(−8p)

=r+−3q+5p+4r+3q+8p

Combine Like Terms:

=r+−3q+5p+4r+3q+8p

=(5p+8p)+(−3q+3q)+(r+4r)

=13p+5r

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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