Answer:
Alice's weight is 100 lbs.
Step-by-step explanation:
Let's denote Jane's weight by J, and Alice's weight by A.
The exercise says that Jane is 20 lbs heavier than Alice. So that if you add 20 lbs to Alice's weight, you get Jane's weight. In equation form:
It also mentions that Jane's weight is 120% that of Alice. So that if you multiply Alice's weight by 1.2, you get Jane's weight. In equation form:
Plugging this second equation onto the first equation, we get:
And now solving for A:
Therefore Alice's weight is 100 lbs.
Answer:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Solution to the problem
Let X the random variable who represents the variable of interest. We know from the problem that the distribution for the random variable X is given by:
We select a sample of size n=64. That represent the sample size.
From the central limit theorem we know that the distribution for the sample mean 
is given by:
The mean for the sample distirbution would be given by:
And the deviation given by:
And then the distribution for the sample mean is:
Answer:
-2m
Step-by-step explanation:
-6+4 = -2 or 4-6 = -2 so -2m
Answer:
do you want us to simplify it? or find the integral?
