First lets distribute the 5x
5x^2 + 30x = -50
Lets divide every term by 5
x^2 + 6x = -10
To complete the square we have to half the b value, which in this case is 6. Then square it.
Half of 6 is 3, 3 squared is 9
Add that to both sides of the equation
x^2 + 6x + 9 = -1
Find the binomial squared
(x+3)^2 (If you're wondering how i got that please comment)
(x+3)^2 = -1
Take the square root of the equation of both sides
(x+3) = +/- i
x = -3 +/- i
x = -3 - i
and
x = -3 + i
Answer:
41x² - 27x + 27
Step-by-step explanation:
Perimeter of Rectangle:
= 2(20x²-12x+4) + 2(5x²-5x+15)
= 40x²-24x+8 + 10x²-10x+30
= 50x²-34x+38
Perimeter of Triangle:
= 6x²+6x+3x+3+3x²-2x+8
= 9x²+7x+11
Difference:
(50x²-9x²)+(-34x+7x)+(38-11)
= 41x² - 27x + 27
Answer:
If b is 3, x=-1
Step-by-step explanation:
-2(3x-5)=16
use distributive property
-6x+10=16
take 10 away from both sides
-6x=6
divide both sides by -6
x=-1
