Answer: 0.5
Step-by-step explanation:
Given : Adult male heights have a normal probability distribution .
Population mean : ![\mu = 70 \text{ inches}](https://tex.z-dn.net/?f=%5Cmu%20%3D%2070%20%5Ctext%7B%20inches%7D)
Standard deviation: ![\sigma= 4\text{ inches}](https://tex.z-dn.net/?f=%5Csigma%3D%204%5Ctext%7B%20inches%7D)
Let x be the random variable that represent the heights of adult male.
z-score : ![z=\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
For x=70, we have
![z=\dfrac{70-70}{4}=0](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B70-70%7D%7B4%7D%3D0)
Now, by using the standard normal distribution table, we have
The probability that a randomly selected male is more than 70 inches tall :-
![P(x\geq70)=P(z\geq0)=1-P(z](https://tex.z-dn.net/?f=P%28x%5Cgeq70%29%3DP%28z%5Cgeq0%29%3D1-P%28z%3C0%29%3D1-0.5%3D0.5)
Hence, the probability that a randomly selected male is more than 70 inches tall = 0.5
Answer: Both answers will be
![15x+18](https://tex.z-dn.net/?f=15x%2B18)
Step-by-step explanation:
Since we have given that
Cost of soccer balls = $15
Cost of baseball = $6
Cost of sweat socks = $5
a) Mr. Tonkery bought x number of soccer balls and 3 base balls .
So, our algebraic expression will be
![15x+3\times 6\\\\=15x+18](https://tex.z-dn.net/?f=15x%2B3%5Ctimes%206%5C%5C%5C%5C%3D15x%2B18)
b) Dennis, Eddie and Felix are on a base ball team. They each bought a baseball and x pair of sweat socks .
Since there are 3 members in a base ball team ,
Number of base ball they will purchase is given by
![3\times 6=18](https://tex.z-dn.net/?f=3%5Ctimes%206%3D18)
Number of sweat socks they will bought is given by
![5\times x\times 3=15x](https://tex.z-dn.net/?f=5%5Ctimes%20x%5Ctimes%203%3D15x)
Total number they will purchase is given by
![15x+18](https://tex.z-dn.net/?f=15x%2B18)
Hence, both answers will be
![15x+18](https://tex.z-dn.net/?f=15x%2B18)
Answer:
-10°F, -13°F, and -21°F
Step-by-step explanation:
we are looking for a temperature that is less than -8
-10°F, -13°F, and -21°F are all less than -8
Answer:
The student's GPA is 2.8666.
Step-by-step explanation:
A grade is 4.0, B grade is 3.0, C grade is 2.0. For each credit, add the value of the letter grade. So:
Math, 2 credits, grade A: (4x2=8)
English, 5 credits, grade B: (5x3=15)
Physics, 4 credits, grade B: (4x3=12)
German, 4 credits, grade C: (4x2=8)
The numbers add up to 43, then divide by the number of credits (15) to get:
43/15=GPA of 2.8666.