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Nata [24]
3 years ago
12

Answer this pleaseeeee

Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Answer:

<u>Dilation by a scale factor of k results in:</u>

  • (x, y) → (kx, ky)

<u>Considering this the answers are:</u>

  • 1. Option C
  • 2. Option F
  • 3. Option J
  • 4. Option H
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Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

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The diagram shows a circle with centre O. Points A , B, C and D all lie on the circumference of the circle.
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Answer:

The puck travels in a circular path of radius 0.25 m. ... C. away from the centre. D. ... If the speed of the mass at the top of the circle is 3.6

Step-by-step explanation:

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If triangle RST is within Quadrant 2 and csc T = 13/12, what is the value of cotT?
zhuklara [117]

Answer:

\boxed {cot T = -\frac{5}{12}}

Step-by-step explanation:

<u>Finding the missing side</u> :

  • x² = 13² - 12²
  • x² = 169 - 144
  • x = √25
  • x = 5

<u>Taking the cot value</u> :

  • cot T = adjacent / opposite
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Step-by-step explanation:yw

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